Could anyone help me how to get the result as desired in the following code.

A=1:20;
while ~isempty(A)
B=reshape(A,[],2);
B(:,end)=B(end:-1:1,end);
for k=1:size(B,1)
C=B(k,:)
A=[];
end
end

The code executes and gives the following result

C = 1    20
C = 2    19
C = 3    18
C = 4    17
C = 5    16
C = 6    15
C = 7    14
C = 8    13
C = 9    12
C = 10   11

But I want to have the result in the following manner

C = 1    20   4    17   7   14   10  11
C = 2    19   5    16   8   13 
C = 3    18   6    15   9   12

Could anyone please help me on this.

[Constantino Carlos Reyes-Aldasoro]

Hello

It is a bit difficult to help you with this without more information. Do you always have 20 elements? Why do you save the results to C every time?

[jaah navi]

With respect to the above code I am having 20 elements. The reason I am saving it to C every time is that, I need to compare the performance metrices based on the elements

C = 1    20   4    17   7   14   10  11
C = 2    19   5    16   8   13 
C = 3    18   6    15   9   12

that have been stored in C.

[Constantino Carlos Reyes-Aldasoro]

If you need those specific values to run something else, then there is not much point in coding the order. Just store as cells that you can use

C={[1    20   4    17   7   14   10  11],[2    19   5    16   8   13 ],[3    18   6    15   9   12]}

And then use them in your code like

for k=1:3
    C{k}
    % ...
    %...
end

Answer 1

[Mathieu NOE]

hello

after so guess work, I finally change the code to this

clc

A=1:20;
B=reshape(A,[],2);
B(:,end)=B(end:-1:1,end);


for ci = 1:3
    C = [];
    ind1 = ci:3:size(B,1);
    for k=1:length(ind1)
        ind2 = ci+(k-1)*3;
        C = [C  B(ind2,:)];
    end
disp(C)
end

and this is the result , as expected :

1 20 4 17 7 14 10 11

2 19 5 16 8 13

3 18 6 15 9 12

maybe those 3 lines should be stored in 3 cells ?

[jaah navi]

Thanks for your help.