Struggling with fminsearch with vector inputs
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Chang seok Ma
am 1 Nov. 2021
Kommentiert: Matt J
am 4 Nov. 2021
Hello,
I am trying to use vector as an input for fminsearch.
clear
clc
R = 1.0080;
sig = 0.75;
tempkgrid = linspace(-20,60,10)';
kgrid = [tempkgrid ; tempkgrid ; tempkgrid];
zgrid = [2;2;2;2;2;2;2;2;2;2;4;4;4;4;4;4;4;4;4;4;6;6;6;6;6;6;6;6;6;6];
K = kgrid;
Z = zgrid;
aconst1 = -20*ones(30,1);
aconst2 = 60*ones(30,1);
obj = @(Kp) (1/(1-1/sig)) * ((Z + K - Kp./R) > 0) .* (Z + K - Kp./R).^(1-1/sig) + ((Z + K - Kp./R) <= 0) * (-999999);
Kp2 = fminsearch(obj,aconst1);
If I run this, I get the following error message. 'Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 30-by-1'
Is there anyway I can run this?
Thanks in advance.
0 Kommentare
Akzeptierte Antwort
Matt J
am 1 Nov. 2021
Bearbeitet: Matt J
am 1 Nov. 2021
Your objective function is not returning a scalar value at Kp=aconst1. We cannot know what objective you truly intended.
Regardless though, you will not have much luck using fminsearch on a problem with 30 unknowns. It is designed for much smaller problems (<7 unknowns or thereabouts).
2 Kommentare
Matt J
am 3 Nov. 2021
Bearbeitet: Matt J
am 3 Nov. 2021
It is theoretically proven to converge only for problems with a single unknown, but empirically, it tends to work well up to about 6 unknowns.
Also, the computation time per iteration can increase steeply with the number of unknowns, N. The algroithm requires N+1 evaluations of the objective function per iteration, so if each evaluation is O(N), the computational cost of the whole iteration will be O(N^2).
Weitere Antworten (1)
John D'Errico
am 1 Nov. 2021
Bearbeitet: John D'Errico
am 1 Nov. 2021
Fminsearch should NEVER be used with more than around say 6-8 unknowns. 30 unknowns is just impossible for fminsearch. PERIOD. I've not even looked at whether your problem is well-posed, as fminsearch is a waste of your time here.
2 Kommentare
Matt J
am 4 Nov. 2021
You can always try, but I think it will be both more reliable and faster if you solve one equation at a time using fzero(). Or, if your eqautions happen to be polynomials like above, you should use roots().
Siehe auch
Kategorien
Mehr zu Creating, Deleting, and Querying Graphics Objects finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!