Filter löschen
Filter löschen

Need to make a nested loop

2 Ansichten (letzte 30 Tage)
Tony Montgomery
Tony Montgomery am 4 Okt. 2014
Kommentiert: Tony Montgomery am 5 Okt. 2014
I'm new at matlab, here's what i need to do. I've got a inner loop used to solve a polynomial at a given x value, But I need to evaluate the polynomial at 100 x-values. I need help making the loop work. here is what i have that does not work.
i = 1;
j = 0;
while j <= 100;
j = j+1;
%Loop used to find the solution to the polynomial at given point
while i <= n;
soln(j,i) = P(1,i)*(Xval(j)).^(n-i);
i = i + 1;
end
end
%soln
%Eval = sum(soln)
The inner loop (used to solution to the polynomial) does work. I need to run the inner loop 11 times(for a degree 10 polynomial) and the outter loop 100 times (for 100 xvalues). How can I make this work? I suck at matlab.
  2 Kommentare
per isakson
per isakson am 4 Okt. 2014
Bearbeitet: per isakson am 4 Okt. 2014
Why not for-loops? Your question is it on loops or polynomials?
Tony Montgomery
Tony Montgomery am 4 Okt. 2014
My question is on loops. I need to solve a polynomial to 100 x values. I need those values stored into an array to be compared to the actual solution of the function I was given. My question is, How do i run the inner loop 10 times, for every 100 x values that i need?

Melden Sie sich an, um zu kommentieren.

Antworten (3)

per isakson
per isakson am 4 Okt. 2014

per isakson
per isakson am 4 Okt. 2014
Is this what you try to do? With my variable names
n = 11;
P = 1 : n; % the simplest data I can think of
X = ones( 1, 100 ); % too allow me to check the result
S = nan( 100, n );
for ii = 1 : 100
for jj = 1 : n
S(ii,jj) = P(1,jj)*(X(ii)).^(n-jj);
end
end
>> S(1,:)
ans =
1 2 3 4 5 6 7 8 9 10 11

Image Analyst
Image Analyst am 4 Okt. 2014
Why not just polyfit() and not bother with all that mess?
coefficients = polyfit(P, Xval, 10); % 10 is way too high for a polynomial!
  1 Kommentar
Tony Montgomery
Tony Montgomery am 5 Okt. 2014
I did, but instructor will not accept. Must do it the long way. I found another way around just not very neat. thanks anyway

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Polynomials finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by