Crop an image using coordinate
53 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
hu
am 2 Okt. 2014
Kommentiert: Image Analyst
am 16 Mai 2022
Hi,
How can I crop an image by having the top left coordinate (X1,Y1) and bottom right (X2,Y2).
I2 = imcrop(im,[x1 y1 x2 y2])
does not seem to work?
Thanks
3 Kommentare
nisa sarfraz
am 14 Jan. 2020
I=imread(images(1).name); %crop one to get rect
this line of code give error of index matrix dimension exeeds. kindly suggest some solution
Image Analyst
am 14 Jan. 2020
Nisa, start a new question, and give the code that you used to load up your images structure (was it the dir function?). Your images structure is evidently empty, meaning it found not images.
filePattern = fullfile(pwd, '*.png');
images = dir(filePattern);
if isempty(images)
message = sprintf('No PNG images found in folder %s\n', pwd)
uiwait(errordlg(message))
return;
end
thisImage=imread(images(1).name);
imshow(thisImage)
% Crop one to get rect
croppedImage = imcrop(thisImage);
Akzeptierte Antwort
Image Analyst
am 2 Okt. 2014
You used 151 instead of 115 in your width. Here, try this:
grayImage = imread('circuit.tif');
subplot(1,2,1);
imshow(grayImage);
h = impixelinfo();
axis on;
I2 = imcrop(grayImage,[115, 89, 161-115,142-89]);
subplot(1,2,2);
imshow(I2)
axis on;
2 Kommentare
Aparna Sivakumar
am 16 Mai 2022
Hi how could you get the follwing values>? imcrop(grayImage,[115, 89, 161-115,142-89]);
Image Analyst
am 16 Mai 2022
I don't know. It looks like the original poster changed/edited his post. It no longer mentions 151 and he removed the image.
Weitere Antworten (3)
John BG
am 4 Mär. 2017
Bearbeitet: John BG
am 4 Mär. 2017
Hi Hu
A=imread('im1.jpg');imshow(A)
p=ginput(2)
p1max=max(p(:,1));p2max=max(p(:,2));p1min=min(p(:,1));p2min=min(p(:,2));
A(:,[1:p1min],:)=[];
A([1:p2min],:,:)=[];
A(:,[uint64(p1max-p1min+1):end],:)=[];
A([uint64(p2max-p2min+1):end],:,:)=[];
imshow(A)
EXPLANATION
1.
as example let's start with this image
A=imread('im1.jpg');imshow(A)
2. Selecting 2 diagonal points that define the borders you want to remove. I use command ginput but you already have the values
p=ginput(2)
3. Calculating border values from ginput points
p1max=max(p(:,1));p2max=max(p(:,2));p1min=min(p(:,1));p2min=min(p(:,2));
4. Removing on borders, one side of the frame at a time
A(:,[1:p1min],:)=[];
A([1:p2min],:,:)=[];
A(:,[uint64(p1max-p1min+1):end],:)=[];
A([uint64(p2max-p2min+1):end],:,:)=[];
5.
Check
imshow(A)
Hu
if you find these lines useful would you please mark my answer as Accepted Answer?
To any other reader, if you find this answer of any help please click on the thumbs-up vote link,
thanks in advance for time and attention
John BG
0 Kommentare
Nalini Vishnoi
am 2 Okt. 2014
You can try using the following command
I2 = imcrop(im,[x1 y1 x2-x1 y2-y1]);
imcrop uses the following syntax:
I2 = imcrop(I,RECT);
where RECT is a 4-element vector with the form [XMIN YMIN WIDTH HEIGHT];
3 Kommentare
Geoff Hayes
am 2 Okt. 2014
hu - please describe what you mean by ...does not work. Perhaps provide an example pair of coordinates with what you expect to be the desired outcome.
Amruta Talreja
am 4 Mär. 2017
I2 = imcrop(B1,[12659 11677 11281 12661]); imshow(I2); I wrote this code and i am getting a blank screen. plz help.
4 Kommentare
Warid Islam
am 12 Jul. 2019
Hi,
Is it possible to crop the image manually without using a rectangle? For example, can I create a boundary manually with a mouse on the Matlab image and display the cropped image separately?
Image Analyst
am 13 Jul. 2019
If you use imcrop() without any arguments, you'll be in interactive drawing mode.
Siehe auch
Kategorien
Mehr zu Image Processing and Computer Vision finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!