Converting a binary matrix to decimal.
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I change the 3-bit binary matrix(a, e) to decimal -> change the decimal to a 4-bit binary matrix -> Add changed a and e = A
The following errors occur.
bin2dec :
The input argument must be a cell type array consisting of a character type vector, string type, or character type vector.
What is the way to correct the error?
Below is the code content.
function A = Xasum(X)
N = 64;
for k = 1 : N
x = X(k, :);
a = x(:, [1,2,3]);
e = x(:, [4,5,6]);
bin2dec(a);
dec2bin((a),4);
bin2dec(e);
dec2bin((e),4);
A = (a + e)';
end
end
X = [0 0 0 0 0 0;
0 0 0 0 0 1;
0 0 0 0 1 0;
0 0 0 0 1 1;
0 0 0 1 0 0;
0 0 0 1 0 1;
0 0 0 1 1 0;
0 0 0 1 1 1;
0 0 1 0 0 0;
0 0 1 0 0 1;
0 0 1 0 1 0;
0 0 1 0 1 1;
0 0 1 1 0 0;
0 0 1 1 0 1;
0 0 1 1 1 0;
0 0 1 1 1 1;
...
...
...
1 1 1 1 0 1;
1 1 1 1 1 0;
1 1 1 1 1 1;
];
0 Kommentare
Antworten (1)
Jan
am 23 Okt. 2021
Bearbeitet: Jan
am 23 Okt. 2021
The error message is clear: bin2dec requires a CHAR vector as input or a cell string. See:
doc bin2dec
You provide a numerical vector consisting on 1s and 0s.
This part of the code does not assigbn the results to a varible, so the computations are lost and only a waste of time:
bin2dec(a);
dec2bin((a),4);
bin2dec(e);
dec2bin((e),4);
What do you want to achieve? a and e are not changed here.
The result A is overwritten in each iteration:
A = (a + e)';
At the end, A contains the value of the last iteration k=N only. Is this wanted?
What is the wanted output for:
X = [0 0 0 0 0 0; ...
0 0 0 0 0 1; ...
0 0 0 0 1 0];
3 Kommentare
Jan
am 24 Okt. 2021
Again: What is the wanted output for the given X?
Splitting the array is easy:
X = [0 0 0 0 0 0; ...
0 0 0 0 0 1; ...
0 0 0 0 1 0];
X1 = X(:, 1:3)
X2 = X(:, 4:6)
Expanding this to 4 bits means inserting columns with zeros:
nRow = size(X, 1);
Y = [zeros(nRow, 1), X1, zeros(nrow, 1), X2];
Siehe auch
Kategorien
Mehr zu Numeric Types finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!