How to normalize a matrix in such a wat that every row sum of X(:,:,i) should be 1 except for ith row

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I have created a matrix X = rand([6,3,6]); i want to normalize this matrix in such a way that every row sum of X(:,:,i) should be 1 except for ith row.
Inside an while(1) loop ,i have
i=randi(n);
Say for example when i=2 that particular row sum should not be equal to one. same goes for other node.How it can be done?
  3 Kommentare
chan
chan am 24 Okt. 2021
in an infinite loop this i (node) value will keep on changing. based on that value of i , the matrix will be normalize except this particular i (node).
if i=2 only that particular row will not be normalize while others row wiil be equal to 1. it will be same for other i's based on the random value generated.
Jan
Jan am 24 Okt. 2021
@IRANI ACHARJAMAYUM: What yre your inputs? How does X = rand([6,3,6]) and an infinite loop with i=randi(n) match? What is the wanted output?
It is still not clear, what you want to achieve. I've posted some code for normalizing the rows of a 3D array except for certain indices. Does it work? If not, what have to be changed?

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Antworten (2)

Cris LaPierre
Cris LaPierre am 23 Okt. 2021
Why not just create a row vector of random numbers, and insert it into a matrix of ones?

Jan
Jan am 23 Okt. 2021
Bearbeitet: Jan am 23 Okt. 2021
X = rand(6, 3, 6);
N = sum(X, 2);
N(sub2ind(size(N), 1:6, ones(1,6), 1:6)) = 1;
Y = X ./ N;
Now sum(Y(i, :, j)) is 1 is i~=j.
sum(Y(1, :, 2))
ans = 1
sum(Y(3, :, 3))
ans = 1.5543

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