Determine where lines intersect
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Hey! Im wondering how i could Determinate the intersect of these two lines. I got the following code.
z0=10000;
dz0=0;
span=[0 250];
[T,Y] = ode45(@function_A,span,[z0 dz0]);
x=linspace(0,300,2000);
plot(T,Y(:,1),'b', x,0,'g');
and this function
function dz = function_A(t,z)
dz = zeros(2,1);
g=9.81;
m=250;
lambda=7.5*10^3;
k0=(m*g)/((250/3.6)^2);
k=@(z)k0.*exp(-z./lambda);
dz(1)=z(2);
dz(2)=-g-(k(z(1)).*abs(z(2))*z(2))/m;
end
Anyone who can help me?
0 Kommentare
Antworten (1)
Mischa Kim
am 29 Sep. 2014
Bearbeitet: Mischa Kim
am 29 Sep. 2014
Hello Andreas, use ode events. This examples shows how to detect events with the bouncing ball problem. Check out the following:
function my_ode()
z0 = 10000;
dz0 = 0;
span=[0 250];
options = odeset('Events',@events);
[T,Y,Te,Ye,Ie] = ode45(@function_A,span,[z0 dz0],options);
x = linspace(0,300,2000);
plot(T,Y(:,1),'b', x,0,'g');
end
function dz = function_A(t,z)
dz = zeros(2,1);
g = 9.81;
m = 250;
lambda = 7.5*10^3;
k0 = (m*g)/((250/3.6)^2);
k = @(z)k0.*exp(-z./lambda);
dz(1) = z(2);
dz(2) = -g-(k(z(1)).*abs(z(2))*z(2))/m;
end
function [value,isterminal,direction] = events(t,y)
% Locate the time when height passes through zero in a
% decreasing direction and stop integration.
value = y(1); % Detect height = 0
isterminal = 1; % Stop the integration
direction = 0; % Negative direction only
end
1 Kommentar
Jan
am 5 Okt. 2014
The function to be integrated contains an abs() . This is a non-smooth function and inconsequence the solution suffers from the problems described here. The step size control of ODE45 must fail at the changes of the sign. To handle this, the step size is reduced until the discontinuity is covered by the rounding errors.
Better use an event function and restart the integration at the discontinuity.
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