how can find size of this objects in a binary image?

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sara
sara am 24 Sep. 2014
Bearbeitet: Image Analyst am 23 Okt. 2021
hi I have a binary image and it has some objects...how can find size of this objects??Is there any toolbox in matlab for this??

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Meshooo
Meshooo am 25 Sep. 2014
Bearbeitet: Meshooo am 25 Sep. 2014
There are many ways to do that. One easy way is to use nnz (Number of nonzero matrix elements).
So if your image is I, then:
I = im2bw (I); %be sure that your image is binary
Total_White_Pixels = nnz(I); % total area based on number of white pixels
Hope that helps you.
  3 Kommentare
sylvester Fok
sylvester Fok am 23 Okt. 2021
what is the units?
Image Analyst
Image Analyst am 23 Okt. 2021
Bearbeitet: Image Analyst am 23 Okt. 2021
@sylvester Fok, the units are "pixels" since nnz() gives a count of elements with non-zero values in an array. If you have the area of a pixel in real world units, like it's 5 square meters per pixel, then you can multiply by that spatial calibration factor, like I do in the attached demo.
Note that this answer just gives the area of all blobs added together, not of single blobs like I showed in my answer below. Essentially:
mask = grayImage > 128; % Create a logical binary image.
props = regionprops(mask, 'Area'); % Find areas of each blob and put into a structure.
allAreas = [props.Area]
Be sure to run my Image Segmentation Tutorial.

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Meshooo
Meshooo am 25 Sep. 2014
Bearbeitet: Meshooo am 25 Sep. 2014
You can do it in few steps. If your input image is I then:
%Step 1: Label each object using the following code.
I = im2bw(I); % be sure your image is binary
L = bwlabel(I); % label each object
%Step 2: see the label of each object
s = regionprops(L, 'Centroid');
imshow(I)
hold on
for k = 1:numel(s)
c = s(k).Centroid;
text(c(1), c(2), sprintf('%d', k), ...
'HorizontalAlignment', 'center', ...
'VerticalAlignment', 'middle');
end
hold off
% Step 3: find the area of the object you want using its label
Obj = (L == 1) % 1 is the label number of the first object.
figure, imshow(Obj);
Area = regionprops(Obj,'Area') % the answer
Now, for example if you want to find the area of object number 3, the just change number 1 to 3.
Obj = (L == 3) where 3 is the label number of the third object.
Area is the number of pixels in the object.
Hope that will help.

Matt J
Matt J am 24 Sep. 2014
How about,
regionprops(...,'Area')

Image Analyst
Image Analyst am 24 Sep. 2014
Bearbeitet: Image Analyst am 23 Okt. 2021
Of course sara. I thought you've already run across my image segmentation tutorial by now. Run it here http://www.mathworks.com/matlabcentral/fileexchange/?term=authorid%3A31862, replacing the coin image with yours. It will tell you the areas, centroids, bounding boxes, coordinates of the perimeter, etc.
Basically, it's
mask = grayImage > 128; % Create a logical binary image.
props = regionprops(mask, 'Area'); % Find areas of each blob and put into a structure.
allAreas = [props.Area]

sara
sara am 25 Sep. 2014
Bearbeitet: sara am 25 Sep. 2014
thanks Image Analyst and Meshooo Matt
I searched and tried this codes befor... but I want to know the size of an object in this image..I don't want to obtain the largest or smallest objects of this image..I want to know just the size of white object.. for simples of this question we can assume that we just have one object in this image...I hope I could explain my question clearly ...I have tow images that are very similar to each other and I want to chose the image that my goal object is larger in it...thanks

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