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for loop

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Hi,I have created the following loop:
for i = 1:5 x = i*2 end
I wish to be able to record each value of the iteration i.e. 2,4,6,8,10 aswell as arrive at the final value of 10 which the above code dies.Could you tell me how to do this? Thanks

Accepted Answer

Grzegorz Knor
Grzegorz Knor on 9 Sep 2011
x = zeros(5,1);
for i = 1:5
x(i) = i*2;
end
disp(x)

More Answers (3)

Andrei Bobrov
Andrei Bobrov on 9 Sep 2011
for i1 = 5:-1:1, x(i1) = i1*2;end
for your case
x = (1:5)*2
or
x = 2:2:10
  3 Comments
Grzegorz Knor
Grzegorz Knor on 9 Sep 2011
nice trick :)

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mohammad
mohammad on 9 Sep 2011
x=[];
for i = 1:5
x =[x;i*2]; %for column matrix
end
OR:
x=[];
for i = 1:5
x =[x,i*2]; %for row matrix
end
  2 Comments
Jan
Jan on 9 Sep 2011
This is working and fast for tiny vectors. But it is really worth to pre-allocate arrays to get familiar with good programming methods. Without pre-allocation, this happens:
1. x is created as empty DOUBLE vector. This needs about 100 bytes for the internal header and 0 bytes for the data.
2. Inside the loop another vector x is created, again 100 bytes header, 8 bytes for the data. The former x is released.
3. In the 2nd iteration the next vector is created, again 100 bytes header, 16 bytes of data, 8 bytes of the formar array are copied. The former x is released.
4. etc.
If the loop runs until N, a total of N*100+prod(1:N)*8 bytes are allocated, filled with zeros, partially released later and prod(1:N-1)*8 bytes are copied.
In consequence you apporach is horribly slow for e.g. 1000 elements and might even crash with an out-of-memory error for larger vectors. Therefore *always* pre-allocate.

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Liam Mescall
Liam Mescall on 9 Sep 2011
Thanks guys

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