How to find a subset matrix in the main matrix and build a new matrix
5 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi everyone,
Suppose I have two matrices A and B. The matrix A is a subset of matrix B (it can be possible that some of arrays or rows of matrix A were missing in matrix B). There is an ID column in the matrix B that rows with a unique ID can be used in building of matrix C.
If there is a similar row of matrix A in the matrix B, then copy this row to the matrix C. In addition, if there is more than one similar unique ID in the matrix B, then copy those ones as well in the matrix C.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/145292/image.jpeg)
For example: second row in matrix A [3,6,8,7,5] is found in the tenth row in the matrix B. Also, there are more than on unique ID (4), then both tenth and eleventh row of matrix B is copied in the matrix C.
Input:
A = [2,4,5,6,7;3,6,8,7,5;2,3,9,8,1;1,8,2,9,2;3,4,5,8,6;7,8,6,5,4;7,9,5,1,2;6,5,2,1,1;4,9,2,3,4;1,8,7,2,6];
B = [1,4,8,9,7,1;2,3,9,8,1,1;8,7,5,1,3,2;6,6,2,9,7,2;1,2,3,1,4,3;3,4,5,8,2,3;2,5,6,9,7,3;1,3,6,7,2,3;4,9,8,7,6,3;3,6,8,7,5,4;1,2,8,3,7,4;7,9,5,1,2,5;1,5,9,7,2,6;6,5,7,1,2,6;1,8,2,9,2,6;7,8,9,1,3,7;1,3,5,4,8,7;1,6,9,7,1,7;4,5,9,7,2,8;1,2,3,6,9,8;7,8,9,9,1,9;4,7,2,3,1,9;5,6,8,9,7,9;6,8,2,4,1,10;1,8,7,2,6,10;2,3,5,9,7,11;7,5,6,9,3,11;6,5,2,1,1,11;2,3,6,7,8,12];
Output:
C = [3,6,8,7,5,4;1,2,8,3,7,4;1,4,8,9,7,1;2,3,9,8,1,1;1,5,9,7,2,6;6,5,7,1,2,6;1,8,2,9,2,6;7,9,5,1,2,5;2,3,5,9,7,11;7,5,6,9,3,11;6,5,2,1,1,11;6,8,2,4,1,10;1,8,7,2,6,10];
Thanks.
0 Kommentare
Akzeptierte Antwort
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!