How to print result in MATLAB?
102 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Phan
am 21 Aug. 2014
Kommentiert: Phan
am 21 Aug. 2014
Dear everyone,
Please help me to solve this problem. I have two arrays like this:
Name=['ABC-8' 'S8' 'EG8'];
Thick=[25 16 12];
I want to create an array like this:
Z=['ABC-825' 'S816' 'EG812'];
Can anyone help me to write a code to make that array?
Thank you so much!
0 Kommentare
Akzeptierte Antwort
Aniruddha Phatak
am 21 Aug. 2014
Robert is right, you must define it as a cell array.
name={'ABC-8' 'S8' 'EG8'};
thick=[25 16 12];
for i=1:3
thin{i} = [ num2str( thick(i) ) ];
z{i} = strcat(name{i},thin{i});
end
disp(z);
0 Kommentare
Weitere Antworten (3)
David Sanchez
am 21 Aug. 2014
define your Name array as a cell, then:
Name={'ABC-8' 'S8' 'EG8'};
Thick=[25 16 12];
Z =cell(numel(Name),1);
for k=1:numel(Name)
Z{k} = strcat(Name{k},num2str(Thick(k)));
end
>> Z
Z =
'ABC-825'
'S816'
'EG812'
Guillaume
am 21 Aug. 2014
Bearbeitet: Guillaume
am 21 Aug. 2014
Assuming that Name is a cell array, that is
Name = {'ABC-8' 'S8' 'EG8'};
(otherwise as you wrote it, it's just a single string). Then:
Z = cellfun(@(s,n) sprintf('%s%d', s, n), Name, num2cell(Thick), 'UniformOutput', false);
will do it. Note that Z has to be a cell array.
Robert Cumming
am 21 Aug. 2014
The two answers on here are correct - however if you take the for loop from one and the sprintf from the other you get a faster result:
Z =cell(1,numel(Name));
for k=1:numel(Name)
Z{k} = sprintf ( '%s%d', Name{k}, Thick(k) );
end
Speed evidence:
clear
clc
Name={'ABC-8' 'S8' 'EG8'};
Thick=[25 16 12];
tic
ZA =cell(1,numel(Name));
for k=1:numel(Name)
ZA{k} = strcat(Name{k},num2str(Thick(k)));
end
toc
tic
ZB = cellfun(@(s,n) sprintf('%s%d', s, n), Name, num2cell(Thick), 'UniformOutput', false);
toc
tic
ZC =cell(1,numel(Name));
for k=1:numel(Name)
ZC{k} = sprintf ( '%s%d', Name{k}, Thick(k) );
end
toc
isequal ( ZA, ZB )
isequal ( ZA, ZC )
Elapsed time is 0.011248 seconds.
Elapsed time is 0.011344 seconds.
Elapsed time is 0.006111 seconds.
3 Kommentare
Robert Cumming
am 21 Aug. 2014
For this type of question you could solve it in many ways....
I just highlight this as many people overlook the simple for loop and the fact that sprintf is the fastest way for handling strings...
Siehe auch
Kategorien
Mehr zu Characters and Strings finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!