draw two 3D curve but can't hold them in one figure
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
the first curve is a solution of a differential equation
function dy=eq3(t,y)
dy=zeros(3,1);
dy(1)=-680*(y(1)-100000)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
dy(2)=-680*(y(2)-340*t)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
dy(3)=-680*(y(3)-10000)/sqrt((y(1)-100000)^2+(y(2)-340*t)^2+(y(3)-10000)^2);
end
and the second one is a line in a 3Dspace
[t,y]=ode45('eq3',[0:0.01:202],[0,0,0]);
plot3(y(:,1),y(:,2),y(:,3))
grid on
hold on
T=0:0.5:200;
X=100000;
Y=340*T;
Z=10000;
plot3(X,Y,Z,'r')
xlabel('x轴')
ylabel('y轴')
zlabel('z轴')
but they don't show up together
0 Kommentare
Antworten (1)
Aniruddha Katre
am 20 Aug. 2014
The reason why the second plot does not show up is because the variables "X" and "Z" are both scalars while "Y" is a vector. You can just convert "X" and "Z" to vectors of the same dimensions as "Y" and the plot should work. Assuming you want to keep "X" and "Z" constant, you can convert them to vectors in the following manner:
X=100000*ones(length(T),1);
Z=10000*ones(length(T),1);
2 Kommentare
Image Analyst
am 20 Aug. 2014
You can "thank" him by officially "Accepting" his answer. It will give him reputation points.
Siehe auch
Kategorien
Mehr zu 2-D and 3-D Plots finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!