Fibonacci sequence that fills an n*n matrix
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Hey everybody. I'm trying to create an n x n matrix where the first two elements are input as well as n. It needs to fill the matrix row by row with each successive summation. I used a loop, but I'm welcome to other suggestions. Here's my code.
n=input('n=\n');
E1=input('First element=\n');
E2=input('Second element=\n');
fib=zeros(n,n);
fib(1)=E1;
fib(2)=E2;
k=3;
for k=3:size(fib);
fib(n/n,k)=fib(k-1)+fib(k-2);
end
fib
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Antworten (4)
the cyclist
am 8 Aug. 2014
Bearbeitet: the cyclist
am 8 Aug. 2014
Instead of
fib(1)=1;
fib(2)=0;
I assume you meant
fib(1)=E1;
fib(2)=E2;
John D'Errico
am 8 Aug. 2014
Bearbeitet: John D'Errico
am 9 Aug. 2014
Adam - did you really intend to write it as:
fib(n/n,k)=fib(k-1)+fib(k-2);
Why would you use fib(n/n,k) for an assignment?
Surely you see that n/n is 1. So why not just assign it as
fib(1,k)=fib(k-1)+fib(k-2);
In fact, I have no idea why you are talking about an n*n matrix. There are n elements, not n*n elements.
You are creating a vector of length n. Note that when you index into the matrix, with f(k), you are treating it as a vector. So what do you intend when you talk about an nxn matrix?
And there is no need to initialize k before the start of the for loop. The for loop creates k as a variable.
As far as how to create a matrix of Fibonacci numbers, there are many ways to do so. The simplest way is to use filter, but that is not so obvious how it works if you are just learning to use a loop for the purpose.
n = input('n=\n');
fib = zeros(1,n);
fib(1) = input('First element=\n');
fib(2) = input('Second element=\n');
for k=3:n
fib(k) = fib(k-1) + fib(k-2);
end
fib
If you wish to create an array, then you need to explain what form it must take.
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John Jairo Aguirre Sanchez
am 31 Dez. 2018
clc
clear
%matriz fibonacci
%dimension de la matriz cuadrada
n=6;
h=zeros(n);
%matriz
format longg
for i=1:n
h(1,1)=1;
h(1,2)=1;
for j=3:n
h(i,j)=h(i,j-2)+h(i,j-1);
end
end
for i=2:n
for j=1:n;
if j==1;
h(i,j)=h(i-1,n)+h(i-1,n-1);
else if j==2
h(i,j)=h(i-1,n)+h(i,j-1);
else
h(i,j)=h(i,j-2)+h(i,j-1);
end
end
end
end
h
0 Kommentare
Sahiro Ortega Campoverde
am 9 Okt. 2022
for i=2:n
for j=1:n;
if j==1;
h(i,j)=h(i-1,n)+h(i-1,n-1);
else if j==2
h(i,j)=h(i-1,n)+h(i,j-1);
else
h(i,j)=h(i,j-2)+h(i,j-1);
end
end
end
end
h
0 Kommentare
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