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How to plot cirlces around this spots..?

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Nimisha
Nimisha am 5 Aug. 2014
Kommentiert: Image Analyst am 7 Aug. 2014
I have this image of blood cells. I want to draw circles around it..
The code is :
im = imread('image.jpg');
im = im(:,:,3);
minR=34; maxR=40; thresh=0.33; delta=12;
origim = im;
if length(size(im))>2
im = rgb2gray(im);
end
maxR2 = 2*maxR;
hough = zeros(size(im,1)+maxR2, size(im,2)+maxR2, maxR-minR+1);
[X Y] = meshgrid(0:maxR2, 0:maxR2);
Rmap = round(sqrt((X-maxR).^2 + (Y-maxR).^2));
Rmap(Rmap<minR | Rmap>maxR) = 0;
edgeim = edge(im, 'canny', [0.1 0.2]);
[Ey Ex] = find(edgeim);
[Cy Cx R] = find(Rmap);
for i = 1:length(Ex);
Index = sub2ind(size(hough), Cy+Ey(i)-1, Cx+Ex(i)-1, R-minR+1);
hough(Index) = hough(Index)+1;
end
twoPi = 0.9*2*pi;
circles = zeros(0,4);
for radius = minR:maxR
slice = hough(:,:,radius-minR+1);
twoPiR = twoPi*radius;
slice(slice<twoPiR*thresh) = 0;
[y x count] = find(slice)
circles = [circles; [x-maxR, y-maxR, radius*ones(length(x),1), count/twoPiR]];
end
circles = sortrows(circles,-4);
i = 1;
while i<size(circles,1)
j = i+1;
while j<=size(circles,1)
if sum(abs(circles(i,1:3)-circles(j,1:3))) <= delta
circles(j,:) = [];
else
j = j+1;
end
end
i = i+1;
end
if nargout==0 % Draw circles
figure, imshow(origim), hold on;
for i = 1:size(circles,1)
x = circles(i,1)-circles(i,3);
y = circles(i,2)-circles(i,3);
w = 2*circles(i,3);
rectangle('Position', [x y w w], 'EdgeColor', 'red', 'Curvature', [1 1]);
end
hold off;
end
But it is not working.. Can anyone help to solve this..? please help..
  2 Kommentare
Star Strider
Star Strider am 6 Aug. 2014
Image processing isn’t an area of my expertise, but your image is.
What do you mean by ‘spots’? You have one polymorphonuclear leukocyte, and a large number of largely abnormal erythrocytes. The small ‘spots’ within the red cells are Howell-Jolly bodies (remnant DNA normally eliminated in the spleen), and the red cells that do not contain them are spherocytes (smaller than normal red cells lacking the normal central concavity).
Do you want to identify the red cells (and estimate their sizes), the Howell-Jolly bodies, or something else?
Nimisha
Nimisha am 6 Aug. 2014
Yes i want to detect leukocyte and erythrocytes. And need to count them.. i tried using above code.
but it not work.. it seems correct to me.. then why..?
do youknow any hough transform method for it..?

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Antworten (2)

Dasharath Gulvady
Dasharath Gulvady am 5 Aug. 2014
Bearbeitet: Dasharath Gulvady am 5 Aug. 2014
Nimisha, By executing your code, I could see that the resulting "circles" is a 0-by-1 empty matrix. It looks like the issue is with the values of the variables “thresh”,” minR”, “maxR” which are hardcoded. Refer to my comments below for one of the for-loops, where I think the issue is:
for radius = minR:maxR
slice = hough(:,:,radius-minR+1); % why is minR hard coded?
twoPiR = twoPi*radius ;
% values in "slice" are small compared to the value "twoPiR*thresh". Hence the resulting "slice" will contain all zeros.
slice(slice<twoPiR*thresh) = 0;
% Since "slice" has all zeros, x and y are empty matrices
[y x count] = find(slice);
% Since x and y are empty matrices, "circles" is an empty matrix
circles = [circles; [x-maxR, y-maxR, radius*ones(length(x),1), count/twoPiR]];
%circles
end
I would suggest taking a look at the hard coded values at the beginning of your code and change them appropriately. Since the code is pretty big, feel free to add some comments in your code which would help in understanding what exactly you are trying to achieve and how you are doing it.

Image Analyst
Image Analyst am 6 Aug. 2014
Bearbeitet: Image Analyst am 6 Aug. 2014
Have you tried imfindcircles? Here is Brett's demo: http://www.mathworks.com/matlabcentral/fileexchange/34365-findcirclesgui (Brett works at The Mathworks)
But what do you REALLY want to do? I'm sure drawing circles it not it - that's not useful. Do you want the count, the average equivalent circular diameter, the area fraction, or what??? How about doing color segmentation like I show you in my File Exchange. Or maybe you want to do something like this: http://www.mathworks.com/products/demos/image/color_seg_k/ipexhistology.html
  2 Kommentare
Nimisha
Nimisha am 7 Aug. 2014
im = imread('image.jpg');
im = rgb2gray(im);
e = edge(im, 'canny');
radii = 20:1:55;
b = e;
rrange = radii;
% get indices of non-zero features of b
[featR, featC] = find(b);
% set up accumulator array - with a margin to avoid need for bounds
[nr, nc] = size(b);
nradii = length(rrange);
margin = ceil(max(rrange));
nrh = nr + 2*margin; % increase size of accumulator
nch = nc + 2*margin;
h = zeros(nrh*nch*nradii, 1, 'uint32'); % 1-D for now, uint32 a touch
% get templates for circles at all radii - these specify accumulator
% elements to increment relative to a given feature
tempR = []; tempC = []; tempRad = [];
for i = 1:nradii
r = rrange(i);
l = round(r/sqrt(2));
if round(sqrt(r.^2 - l.^2)) < l % if crosses diagonal
l = l-1;
end
% generate coords for 1/8 of the circle, a dot on each row
x0 = 0:l;
y0 = round(sqrt(r.^2 - x0.^2));
% Check for overlap
if y0(end) == l
l2 = l;
else
l2 = l+1;
end
% assemble first quadrant
x = [x0 y0(l2:-1:2)];
y = [y0 x0(l2:-1:2)];
% add next quadrant
x0 = [x y];
y0 = [y -x];
% assemble full circle
x = [x0 -x0];
y = [y0 -y0];
end
tR = x;
tC = y;
tempR = [tempR tR]; %#ok<*AGROW>
tempC = [tempC tC];
tempRad = [tempRad repmat(i, 1, length(tR))];
% Convert offsets into linear indices into h - this is similar to sub2ind.
tempInd = uint32( tempR+margin + nrh*(tempC+margin) + nrh*nch*(tempRad-1) );
featInd = uint32( featR' + nrh*(featC-1)' );
% Loop over features
for f = featInd
% shift template to be centred on this feature
incI = tempInd + f;
% and update the accumulator
h(incI) = h(incI) + 1;
end
% Reshape h, convert to double, and apply options
h = reshape(double(h), nrh, nch, nradii);
h = h(1+margin:end-margin, 1+margin:end-margin, :);
margin = 0;
H = bsxfun(@rdivide, h, reshape(rrange, 1, 1, length(rrange)));
ip = inputParser;
% required
htest = @(h) validateattributes(h, {'double'}, {'real' 'nonnegative' 'nonsparse'});
ip.addRequired('h', htest);
rtest = @(radii) validateattributes(radii, {'double'}, {'real' 'positive' 'vector'});
ip.addRequired('radii', rtest);
% optional
mtest = @(n) validateattributes(n, {'double'}, {'real' 'nonnegative' 'integer' 'scalar'});
ip.addOptional('margin', 0, mtest);
% parameter/value pairs
stest = @(s) validateattributes(s, {'double'}, {'real' 'nonnegative' 'scalar'});
ip.addParamValue('smoothxy', 0, stest);
ip.addParamValue('smoothr', 0, stest);
ip.addParamValue('threshold', [], stest);
nptest = @(n) validateattributes(n, {'double'}, {'real' 'positive' 'integer' 'scalar'});
ip.addParamValue('npeaks', [], nptest);
nhtest = @(n) validateattributes(n, {'double'}, {'odd' 'positive' 'scalar'});
ip.addParamValue('nhoodxy', [], nhtest);
ip.addParamValue('nhoodr', [], nhtest);
ip.parse(h, radii, 'nhoodxy', 15, 'nhoodr', 21, 'npeaks', 10);
params = ip.Results;
% smooth the accumulator - xy
if params.smoothxy > 0
[m, hsize] = gaussmask1d(params.smoothxy);
% smooth each dimension separately, with reflection
h = cat(1, h(hsize:-1:1,:,:), h, h(end:-1:end-hsize+1,:,:));
h = convn(h, reshape(m, length(m), 1, 1), 'valid');
h = cat(2, h(:,hsize:-1:1,:), h, h(:,end:-1:end-hsize+1,:));
h = convn(h, reshape(m, 1, length(m), 1), 'valid');
end
% smooth the accumulator - r if params.smoothr > 0
sigma = params.smoothhr;
hsize = ceil(2.5*sigma); % reasonable truncation
x = (-hsize:hsize) / (sqrt(2) * sigma);
m = exp(-x.^2);
m = m / sum(m); % normalise
h = cat(3, h(:,:,hsize:-1:1), h, h(:,:,end:-1:end-hsize+1));
h = convn(h, reshape(m, 1, 1, length(m)), 'valid');
end
% set threshold
if isempty(params.threshold)
params.threshold = 0.5 * max(h(:));
end
if isempty(params.nhoodxy) && isempty(params.nhoodxy)
% First approach to peak finding: local maxima
% find the maxima
maxarr = imregionalmax(h);
maxarr = maxarr & h >= params.threshold;
% get array indices
peakind = find(maxarr);
[y, x, rind] = ind2sub(size(h), peakind);
peaks = [x'; y'; radii(rind)];
% get strongest peaks
if ~isempty(params.npeaks) && params.npeaks < size(peaks,2)
[~, ind] = sort(h(peakind), 'descend');
ind = ind(1:params.npeaks);
peaks = peaks(:, ind);
end
else
% Second approach: iterative global max with suppression
if isempty(params.nhoodxy)
params.nhoodxy = 1;
elseif isempty(params.nhoodr)
params.nhoodr = 1;
end
nhood2 = ([params.nhoodxy params.nhoodxy params.nhoodr]-1) / 2;
if isempty(params.npeaks)
maxpks = 0;
peaks = zeros(3, round(numel(h)/100)); % preallocate
else
maxpks = params.npeaks;
peaks = zeros(3, maxpks); % preallocate
end
np = 0;
while true
[vr, r] = max(h);
[vc, c] = max(vr);
[v, k] = max(vc);
c = c(1, 1, k);
r = r(1, c, k);
% stop if peak height below threshold
if v < params.threshold || v == 0
break;
end
np = np + 1;
peaks(:, np) = [c; r; radii(k)];
% stop if done enough peaks
if np == maxpks
break;
end
% suppress this peak
r0 = max([1 1 1], [r c k]-nhood2);
r1 = min(size(h), [r c k]+nhood2);
h(r0(1):r1(1), r0(2):r1(2), r0(3):r1(3)) = 0;
end
peaks(:, np+1:end) = []; % trim
end
% adjust for margin
if params.margin > 0
peaks([1 2], :) = peaks([1 2], :) - params.margin;
end
% We draw the circles found on the image, using both the positions and the
% radii stored in the peaks array.
imshow(im);
hold on;
for peak = peaks
r = peak(3);
l = round(r/sqrt(2));
if round(sqrt(r.^2 - l.^2)) < l % if crosses diagonal
l = l-1;
end
% generate coords for 1/8 of the circle, a dot on each row
x0 = 0:l;
y0 = round(sqrt(r.^2 - x0.^2));
% Check for overlap
if y0(end) == l
l2 = l;
else
l2 = l+1;
end
% assemble first quadrant
x = [x0 y0(l2:-1:2)];
y = [y0 x0(l2:-1:2)];
% add next quadrant
x0 = [x y];
y0 = [y -x];
% assemble full circle
x = [x0 -x0];
y = [y0 -y0];
plot(x+peak(1), y+peak(2), 'g-');
end
hold off
% For above code i got following resultant image.. but it detects wrong circles..? please give solution...
Image Analyst
Image Analyst am 7 Aug. 2014
Just attach the script with the paper clip icon, or else read this: http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup

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