how to develope loop to save the 'n' elements from the vectors

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gourav pandey
gourav pandey am 15 Sep. 2021
Kommentiert: Matt J am 15 Sep. 2021
clc;
clear;
A= [14,51,2,15,........,7 ] % this is known
p1=A[1]
p2=A[2]
.
.
.
.
.
pn=A[n]
%%% i need to use p1,p2,p3,...pn in another equation. so i dont know to to save this elements from A. how to use loop to that it automatically get saved for n elements

Antworten (2)

Matt J
Matt J am 15 Sep. 2021
It is not a good idea to store A(i) in separate variables. You should probably just write your equation in terms of vector operations on A, which you already have.
  2 Kommentare
gourav pandey
gourav pandey am 15 Sep. 2021
Hii Matt, thank you
i fully agree with you. actually, i am a beginner, so no idea how to use.
if my function is in this way
fun= p1*r^2+p2*ln(r)+p3*cos(theta)/r+p4*sin(theta)/r+(pn*r^(-n+2))*cos(n*theta)
then how to do that?
Matt J
Matt J am 15 Sep. 2021
A(1)*r^2+A(2)*ln(r)+A(3)*cos(theta)/r+A(4)*sin(theta)/r+(A(n)*r^(-n+2))*cos(n*theta)

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Awais Saeed
Awais Saeed am 15 Sep. 2021
Although it is not prefered to name variables in a loop but if you striclty want to do this in loops than you can use eval(). Note that using this method is NOT RECOMMENDED. It has been said many times in this forum and by MATLAB itself.
clc;
clear;
A= [14,51,2,15,7]
A = 1×5
14 51 2 15 7
for col = 1:1:size(A,2)
eval(['p',num2str(col),'=A(',num2str(col),')'])
end
p1 = 14
p2 = 51
p3 = 2
p4 = 15
p5 = 7
  1 Kommentar
Stephen23
Stephen23 am 15 Sep. 2021
Bearbeitet: Stephen23 am 15 Sep. 2021
Note that this is slower and more complex than simply using the vector directly.

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