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how to develope loop to save the 'n' elements from the vectors

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gourav pandey
gourav pandey on 15 Sep 2021
Commented: Matt J on 15 Sep 2021
clc;
clear;
A= [14,51,2,15,........,7 ] % this is known
p1=A[1]
p2=A[2]
.
.
.
.
.
pn=A[n]
%%% i need to use p1,p2,p3,...pn in another equation. so i dont know to to save this elements from A. how to use loop to that it automatically get saved for n elements

Answers (2)

Matt J
Matt J on 15 Sep 2021
It is not a good idea to store A(i) in separate variables. You should probably just write your equation in terms of vector operations on A, which you already have.
  2 Comments
Matt J
Matt J on 15 Sep 2021
A(1)*r^2+A(2)*ln(r)+A(3)*cos(theta)/r+A(4)*sin(theta)/r+(A(n)*r^(-n+2))*cos(n*theta)

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Awais Saeed
Awais Saeed on 15 Sep 2021
Although it is not prefered to name variables in a loop but if you striclty want to do this in loops than you can use eval(). Note that using this method is NOT RECOMMENDED. It has been said many times in this forum and by MATLAB itself.
clc;
clear;
A= [14,51,2,15,7]
A = 1×5
14 51 2 15 7
for col = 1:1:size(A,2)
eval(['p',num2str(col),'=A(',num2str(col),')'])
end
p1 = 14
p2 = 51
p3 = 2
p4 = 15
p5 = 7
  1 Comment
Stephen
Stephen on 15 Sep 2021
Note that this is slower and more complex than simply using the vector directly.

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