function to call, code run but didnt print the value

x1=input('x1');
x2=input('x2');
x3=input('x3');
Xvec=[x1,x2,x3]';
 
function Fofx=my_fun1(R1;R2,R3)
R1=((2*Xvec(1)^2)(4*(Xvec(2))*(Xvec(3))*exp(Xvec(1))));
 
R2=(4*Xvec(1)^2)+(2*(Xvec(2)^2))+((Xvec(3)^2)*sin(Xvec(2)));
R3=(Xvec(1)*(Xvec(2)^2))-(4*Xvec(2)*(Xvec(3)^2)*cos(Xvec(1)));
Fofx=[R1;R2;R3]
end

The above program runs, but doesn't give the answer. It gives a warning:

my_fun1 might be unused.

Please help.

Answer 1

[Star Strider]

The code does not actually call ‘my_fun1’.

This version actually does —

% x1=input('x1');
% x2=input('x2');
% x3=input('x3');
% Xvec=[x1,x2,x3]';
Xvec = rand(3,1)

Xvec = 3×1

0.6603 0.3279 0.1597

FofX = my_fun1(Xvec)

FofX = 3×1

0.3535 1.9673 0.0446

 
function Fofx=my_fun1(Xvec)
R1=((2*Xvec(1)^2)*(4*(Xvec(2))*(Xvec(3))*exp(Xvec(1))));
%                ↑ ← MISSING OPERATOR (Mulotiplicatiuon Assumed)
 
R2=(4*Xvec(1)^2)+(2*(Xvec(2)^2))+((Xvec(3)^2)*sin(Xvec(2)));
R3=(Xvec(1)*(Xvec(2)^2))-(4*Xvec(2)*(Xvec(3)^2)*cos(Xvec(1)));
Fofx=[R1;R2;R3];
end

I changed the argument to ‘my_fun1’ since that appeared to be appropriate.

Also, there was a missing operator that I supplied. Change that if I guessed wrong.

.