Replace empty string with NaN in a cell

I have a cell called A={ "20" "25" "25" [] "20" [] "25" "25" "25" "30"}

I would like to replace cell A with A={ "20" "25" "25" "NaN" "20" "NaN" "25" "25" "25" "30"}

Any help is highly appreciate, thank you.

Answer 1

[Stephen23]

A = {"20","25","25",[],"20",[],"25","25","25","30"}

A = 1×10 cell array
    {["20"]}    {["25"]}    {["25"]}    {0×0 double}    {["20"]}    {0×0 double}    {["25"]}    {["25"]}    {["25"]}    {["30"]}

A(cellfun(@isempty,A)) = {"NaN"}

A = 1×10 cell array
    {["20"]}    {["25"]}    {["25"]}    {["NaN"]}    {["20"]}    {["NaN"]}    {["25"]}    {["25"]}    {["25"]}    {["30"]}

Using one string array is likely much better than nesting lots of scalar strings inside a cell array:

B = string(A)

B = 1×10 string array
    "20"    "25"    "25"    "NaN"    "20"    "NaN"    "25"    "25"    "25"    "30"

[Daneisha Blair]

This is perfect! Thank you.

Answer 2

[Awais Saeed]

clc;clear;close all;
A={ "20"	"25"	"25"	[]	"20"	[]	"25"	"25"	"25"	"30"}
% get locations of empty cell elements
idx = cellfun('isempty',A);
% replace those empty cells with NaN
A(idx) = {NaN}

[Daneisha Blair]

Thank you!