How to create an irregular Matrix

Hi, I have a question. I want to know how to create an array of irregular random size, that is me for example when considering a regular array of size nxn, I consider for example that the first 4 squares (A11, A12, A21, A22) represent a single square, the square next square in the same row size is A13 A23 and so on until all the nxn spaces. The requirement is to respect both the length and width of the spaces (if assigned to a row 2 squares, the entire row will contain 2 squares), as well as for columns. These assignments (to be random), I want to assign a number aleatorrio within, for example if I have a large square 2x2, assign this great square a random number. Associate an image with colors exemplifying what I mean, each large square you want to randomly assign a number, for example the yellow square you want to assign more than April 1 thank you very much

http://img59.imageshack.us/img59/9402/exampleiz.png

Answer 1

[Image Analyst]

Not sure I followed all of your explanation. But your picture looks pretty random to me. I think you'd be best off using brute force to construct this Mondrian of an array, perhaps with some help from repmat(). For example

AB = [A B];
CD = [C; D];

Just make sure the rows or columns agree when you do the horizontal or vertical stitching.

[JuanCarlosBodoque]

sorry for the explanation... i don't speak english very well.

I want to create a matrix with a random size (n*m)each row and column are from different size, for example if you consider a regular matrix of 5 columns and 5 rows, in a new matrix, my first column is size 2 columns of the regular matrix, the second 1 column and a third column of size 2 columns of a regular matrix. Same thing for the rows, for example my first row is 1 row of the regular matrix, the second is 3 rows of a regular matrix and the third is 1 row of the regular matrix (that's the reason of the picture).

When i have the irregular matrix created (with random size of columns and rows), i want to assign random numbers from 0 to 100 to the irregular matrix

Illustrating it in my irregular matrix only in the first row it could be something like:

A=[ 2 2 40 95 95 ]

I don't know if now is more clear

thanks

Answer 2

[Oleg Komarov]

% lenght of the side of the square

l = 17;

% Number of row sub-blocks

m = 5;

% Number of column sub-blocks

n = 4;

% Random dimensions of sub blocks

while true
  md = randi([1 l],m,1);
  nd = randi([1 l],1,n);

    md = round(md/sum(md)*l);
    nd = round(nd/sum(nd)*l);

    if sum(md) == l && sum(nd) == l && all(md) && all(nd)
        break
    end
  end

% Build matrix

mdv = zeros(l,1);
mdc = cumsum(md);
mdv([1; mdc(1:end-1)+1]) = 1;

ndv = zeros(1,l);
ndc = cumsum(nd);
ndv([1 ndc(1:end-1)+1]) = 0:n-1;

out = bsxfun(@plus, cumsum(mdv),cumsum(ndv));

% Visualize matrix

imagesc(out)

EDIT

To have bigger dispersion in the dimensions of the sub-blocks when calling randi([1 imax],...) set imax to a bigger value but be aware that the bigger the imax the more likely the condition to break the loop is NOT satisfied, i.e. it will take longer to generate random sub-blocks.