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Convert string of hex to array of dec

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John Ramshur
John Ramshur am 17 Aug. 2011
I need to convert a string of hexidecimal numbers to an array of dec numbers. The string can potentially contain incomplete hex numbers at the beginning and end of the string. See examples below. I'm trying to use this in a data acquisition setup...so execution time could be a factor.
Input String Examples ('/r' = carriage returns:
s1 = '0001h/r0002h/r0003h/r';
s2 = '4h/r0001h/r0002h/r0003h/r00';
Output Desired:
a1 = [1,2,3]
a2 = [1,2,3]

Akzeptierte Antwort

Fangjun Jiang
Fangjun Jiang am 17 Aug. 2011
s1 = '0001h/r0002h/r0003h/r';
s1 = '4h/r0001h/r0002h/r0003h/r00';
str=regexp(s1,'h/r','split');
Ind=cellfun(@length,str);
str=str(Ind==4);
num=hex2dec(str);
  2 Kommentare
John Ramshur
John Ramshur am 17 Aug. 2011
Worked perfectly. Thanks.
Jan
Jan am 17 Aug. 2011
cellfun('prodofsize', str) is faster than cellfun(@length, str).

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Weitere Antworten (1)

Jan
Jan am 17 Aug. 2011
A simpler method, which is substantially faster:
s1 = '0001h/r0002h/r0003h/r';
a1 = sscanf(a, '%xh/r')
But this does not reject the 4 of the string '4h/r0001h/r0002h/r0003h/r00'!
If you mean \r instead /r:
s1 = sprintf('0001h\r0002h\r0003h\r');
a1 = sscanf(a, '%xh')

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