How to construct an array with varying dimension?
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
ramin bba
am 30 Jun. 2014
Kommentiert: ramin bba
am 30 Jun. 2014
I want to save some data using a "for loop". Within each iteration, I will get a 2D matrix (which I want to save). the size of the matrices is NOT the same, i.e. first 10*10, then 23*23, next 20*20 and so on (no pattern between the sizes). I clearly cannot use a 3D matrix to save the data since the third dimension is not constant. I cannot save them manually/separately either since there is a lot of 2D matrices (this is actually why i am putting it in a for loop). I also do NOT know the size of the largest 2D matrix.
what can I use to do the above? cell? structure?
tnx in advance
0 Kommentare
Akzeptierte Antwort
Image Analyst
am 30 Jun. 2014
Yes. Use a cell array. That's what it's meant for. See the FAQ for a good explanation and some good illustrative examples: http://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F
Weitere Antworten (1)
Geoff Hayes
am 30 Jun. 2014
A cell array would work well for this problem. Since you have a for loop, you have an idea of how many matrices you will need to save. Try the following:
% size the cell array where n is the number of iterations in the for loop (and
% the number of matrices to save)
cellArray = cell(n,1);
% iterate
for k=1:n
% do stuff
% save kth matrix A to cell array
cellArray{k} = A;
end
And that is it - all matrices will be saved to the cellArray object.
Siehe auch
Kategorien
Mehr zu Multidimensional Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!