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to make the rectangle move over the image

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ramya raj
ramya raj am 10 Aug. 2011
hai
i am new to matlab i doing a project for locating the optic disc for that i have create a rectangular window and make the window to move the image and calculate the sum of edge diff inside the window and divide that by sum of intensity inside the window
now i have created a window but i don't know how to move the rectangular window
this is my code please help me
_clc; clear all; close all; fundus=imread('D:\10mcs010\im0001.ppm'); grayImage=fundus(:,:,1);
subplot(4, 4, 1);
imshow(grayImage);
title('Original Grayscale Image');
binaryImage = grayImage > 35;
% Display the binary image.
subplot(4, 4, 2);
imshow(binaryImage);
title('Binary Image');
A=[0 0 0;0 1 0;0 0 0];
op=imopen(binaryImage,A);
subplot(4,4,3);
imshow(op);
title('open image');
clos=imopen(op,A);
subplot(4,4,4);
imshow(clos);
title('closeimage');
eror=imopen(clos,A);
subplot(4,4,5);
imshow(eror);
subplot(4,4,6);
maskedRgbImage = bsxfun(@times, fundus, cast(eror,class(fundus)));
imshow(maskedRgbImage);
title('RGB IMAGE');
g=maskedRgbImage(:,:,2);
subplot(4,4,7);
imshow(g);
title ('Green component');
subplot(4,4,8);
imv=conv2(double(g),[1 0 -1],'same');
imshow((imv));
title ('vertical image');
subplot(4,4,9);
imh=conv2(double(g),[1;0;-1],'same');
imshow(imh);
re=imh;
imwrite(re,'horizontal.tif');
title ('horizontal image');
edgesum=abs(imh)+abs(imv);
% % intens=impixel(fundus);
%
% % figure,imshow(edgesum);
% edgediff=abs(imv)-abs(imh);
im = imread('horizontal.tif');
subplot(4,4,10);
imshow(im);
r=rectangle('Position',[10,10,12,560]);
set(r,'edgecolor','w') % change the color of the rectangle to white
title('image with rectangle');_
*BOLD TEXT*
  1 Kommentar
Walter Roberson
Walter Roberson am 20 Aug. 2011
duplicate is at http://www.mathworks.com/matlabcentral/answers/13866-move-rectangle-over-te-image

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Antworten (4)

Jason
Jason am 10 Aug. 2011
You can use imrect and use the mouse to size and move. It returns the position and size.
h = imrect;
pos = h.getPosition();
Jason

Image Analyst
Image Analyst am 10 Aug. 2011
How about using rbbox()? It lets your user draw a box. There's sample code in its help.

ramya raj
ramya raj am 20 Aug. 2011
the rectangle can be created by using rectangle function
which take the syntax of rectangle(x,y,w,h) x - x coordinate y - y coordinate w - width of the rectangle h - height of the rectangle

Walter Roberson
Walter Roberson am 20 Aug. 2011
This seems to me to be a make-work project. Moving a virtual array over the data array would be much much more efficient than drawing a rectangle on the screen and figuring out what is inside the drawn portion.

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