Hello everyone I have an excel file with 2 columns (x and y) and 2111 rows. What my program does as far now is to : call the file from matlab, place all the couples (xi,yi) on the graph and construct one circle for each point of the excel matrix
clc
close all
clear all
DataSelect='celapossofare';
[v,X,vX]=xlsread('celapossofare.xlsx');
x=v(:,1);y=v(:,2);
plot(x,y,'.');
r = x*0 + 1000;
CIP=circles_new(x,y,r);
Now I would like to calculate the overlapping of this circles (that has as centre xi, yi).
Can someone help me?
[EDIT] CHIARA'S "ANSWER" MOVED HERE:
what I did is the following code
d2 = (x2-x1)^2+(y2-y1)^2;
d = sqrt(d2);
t = ((2*r)^2-d2)*(d2);
if r <= d <= 2*r
A = 2*r^2*acos(d2/(2*d*r))-1/2*sqrt(t);
elseif d > 2*r
A = 0;
else % d < r
A = pi*r^2;
end
My problem Is very stupid but I just started to prgram in matlab.
I don't know How to take x,y from a matrix that I have in excel

4 Kommentare

Sara
Sara am 4 Jun. 2014
Do you need the points where the circles intersect or the area of the overlap?
chiara
chiara am 5 Jun. 2014
I would like to calculate the area where the circles overlap Thank you for your comment
Roger Wohlwend
Roger Wohlwend am 5 Jun. 2014
Do you want to know just the size of the area or do you want to know exactly where it is so that you could highlight it in a diagram for example?
chiara
chiara am 5 Jun. 2014
I prefer to know exactly where it is if possible

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 Akzeptierte Antwort

Roger Wohlwend
Roger Wohlwend am 5 Jun. 2014

0 Stimmen

Construct a grid. Calculate for each point the distances to the circle centers. All points whose distances to the circle centers are smaller than the radiuses belong to the overlapping area.

3 Kommentare

John D'Errico
John D'Errico am 5 Jun. 2014
Of course, this will be highly inexact, being equivalent to a very simple integration, essentially rectangle rule. Note that an exact answer was asked for (not that that will be possible.)
Roger Wohlwend
Roger Wohlwend am 5 Jun. 2014
Bearbeitet: Roger Wohlwend am 5 Jun. 2014
Yes, I admit it is not very exact. Perhaps a better solution is taking paper and a pencil and calculate a formula.
Image Analyst
Image Analyst am 5 Jun. 2014
With a fine enough grid, it can be made as close as is needed. Perhaps it's just an exercise in numerical analysis. She could decrease the grid spacing until the answer "levels out" and becomes relatively stable.

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Weitere Antworten (2)

Sara
Sara am 5 Jun. 2014

0 Stimmen

If you have the mapping toolbox, you can use polybool.
chiara
chiara am 5 Jun. 2014

0 Stimmen

What I did is this but I have a silly problem I don't know how to take x1,x2 y1,y2 from a matrix that I have in excel
d2 = (x2-x1)^2+(y2-y1)^2;
d = sqrt(d2);
t = ((2*r)^2-d2)*(d2);
if r <= d <= 2*r
A = 2*r^2*acos(d2/(2*d*r))-1/2*sqrt(t);
elseif d > 2*r
A = 0;
else % d < r
A = pi*r^2;
end

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