About implementation of lsqnonlin
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    SreeHarish Muppirisetty
 am 10 Mai 2014
  
    
    
    
    
    Kommentiert: Matt J
      
      
 am 12 Mai 2020
            Hi
I have time-course data variable 'prodconcnumbers', size 18000X22 meaning 18000 data points for each of the 22 molecules in my model.
I have 30 parameters to be fit.
I invoke fitting using lsqnonlin as follows:
karbitraryvalues (My initial value parameters)=row vector of some 30 starting values.
lb and ub were again assigned bounds.
lsqnonlinoptions=optimset('Algorithm','Levenberg-Marquardt');
[kestimates,errorperspecies]= lsqnonlin(@lsqnonlin_fun, karbitraryvalues,lb,ub,lsqnonlinoptions);
So, first I built my objfunction as follows:
for eachspecies from 1 to 22
errorpermolecule(eachspecies)=prodconcnumbers(:,eachspecies)-estimatedconcnumbers(:,eachspecies);
end
So, in conclusion, my obj.function I want to minimize errorperspecies is of length 22 where as I have 30 parameters to b estimated using this lsqnonlin.
I am getting the following error:
    ??? Error using ==> lsqncommon at 102
    Levenberg-Marquardt and Gauss-Newton algorithms do not handle bound constraints and trust-region-reflective algorithm requires at least as
    many equations as variables; aborting.
What mistake am I doing? Appreciate your time and help.
2 Kommentare
  Matt J
      
      
 am 11 Mai 2014
				lsqcurvefit might be simpler here than lsqnonlin. Your data comparison is simple subtraction.
  Matt J
      
      
 am 12 Mai 2020
				Abdelwahab Afifi's comment moved here:
How you define your objective function interms of the variables' vector  of length 30 ?
Akzeptierte Antwort
  Matt J
      
      
 am 11 Mai 2014
        Since you have bound constraints, there was no point choosing the Levenberg-Marquardt algorithm, since it will not handle those. When it saw that you were applying bounds, lsqnonlin defaulted back to the trust-region-reflective algorithm.
The other problem was that you are trying to fit 30 parameters with only 22 data points. The trust-region-reflective algorithm cannot process under-determined problems, but even if it could, you would get poor results because your problem is undetermined.
Find more data points with which to do the fit.
4 Kommentare
  Matt J
      
      
 am 12 Mai 2014
				The code you've shown suggests that your objective function is only generating one error term per molecule for a total of 22 error measurements. If you really have 18000*22 measurements, couldn't you be returning the error for each of those?
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