If else condition to determine if a year is a leap year

45 Ansichten (letzte 30 Tage)
chafah zachary
chafah zachary am 7 Mär. 2014
Kommentiert: Rik am 31 Mär. 2020
Hi there. Given a variable Y which stores a year in the 20th century (between 1901 and 2000), write MATLAB code to create a variable Days and assign it a value of 366 if the year is a leap year or a value of 365 otherwise.

Akzeptierte Antwort

Jos (10584)
Jos (10584) am 7 Mär. 2014
function Days = GetDays (Y)
if isLeapYear(Y)
Days = 365 ;
else
Days = 366 ;
end
Now your problem is to write second function IsLeapYear that returns true for leap years. (hint: see Nitin's answer)

Weitere Antworten (3)

Nitin
Nitin am 7 Mär. 2014
These are the conditions for a leap year :
  • The year is evenly divisible by 4;
  • If the year can be evenly divided by 100, it is NOT a leap year, unless;
  • The year is also evenly divisible by 400. Then it is a leap year.
I have done the first part, I'll leave the rest to you to implement
if mod(year,4)== 0 % use the modulo operator to check for remainder
days == 366
else
days == 365
end

Ian
Ian am 8 Sep. 2016
ndays = datenum(Y+1,0,0) - datenum(Y,0,0);
isleap = ndays == 366;

Shikhar Srivastava
Shikhar Srivastava am 28 Mär. 2020
Bearbeitet: Shikhar Srivastava am 28 Mär. 2020
if(year/4==0 || year/400==0 && ~((year/100==0)))
  4 Kommentare
Rik
Rik am 31 Mär. 2020
Complete code posted as answer in another thread:
%sir, i wrote this code,but it is passing nly random leap yeara,can u point out the mistake.%
function valid=valid_date(year,month,day)
if(year/4==0 || (year/400==0 && ~((year/100==0))))
if(3<=month && month<13 || month==1 && 1<=day && day<32)
valid=true;
elseif(month==2 && 1<=day && day<30)
valid=true;
else
valid=false;
end
else
if(3<=month && month<13 || month==1 && 1<=day && day<32)
valid=true;
elseif (month==2 && 1<=day && day<29)
valid=true;
else
valid=false;
end
end
Rik
Rik am 31 Mär. 2020
You are using division. Consider the year 2004, which was a leap year. What happens for each of your checks?
year/4==0% year/4 is 501, so this returns false
year/400==0% year/400 is 5.01, so this returns false
~(year/100==0)% year/100 is 20.04, so this returns true
%so your if is this:
if false || (false && true)
If you describe it with words, what is the condition to check if a year is a leap year?

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Graphics Object Programming finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by