If else condition to determine if a year is a leap year

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chafah zachary
chafah zachary am 7 Mär. 2014
Kommentiert: Rik am 31 Mär. 2020
Hi there. Given a variable Y which stores a year in the 20th century (between 1901 and 2000), write MATLAB code to create a variable Days and assign it a value of 366 if the year is a leap year or a value of 365 otherwise.

Akzeptierte Antwort

Jos (10584)
Jos (10584) am 7 Mär. 2014
function Days = GetDays (Y)
if isLeapYear(Y)
Days = 365 ;
Days = 366 ;
Now your problem is to write second function IsLeapYear that returns true for leap years. (hint: see Nitin's answer)

Weitere Antworten (3)

Nitin am 7 Mär. 2014
These are the conditions for a leap year :
  • The year is evenly divisible by 4;
  • If the year can be evenly divided by 100, it is NOT a leap year, unless;
  • The year is also evenly divisible by 400. Then it is a leap year.
I have done the first part, I'll leave the rest to you to implement
if mod(year,4)== 0 % use the modulo operator to check for remainder
days == 366
days == 365

Ian am 8 Sep. 2016
ndays = datenum(Y+1,0,0) - datenum(Y,0,0);
isleap = ndays == 366;

Shikhar Srivastava
Shikhar Srivastava am 28 Mär. 2020
Bearbeitet: Shikhar Srivastava am 28 Mär. 2020
if(year/4==0 || year/400==0 && ~((year/100==0)))
  4 Kommentare
Rik am 31 Mär. 2020
You are using division. Consider the year 2004, which was a leap year. What happens for each of your checks?
year/4==0% year/4 is 501, so this returns false
year/400==0% year/400 is 5.01, so this returns false
~(year/100==0)% year/100 is 20.04, so this returns true
%so your if is this:
if false || (false && true)
If you describe it with words, what is the condition to check if a year is a leap year?

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