FRF
11 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
[EDIT: 20110715 11:09 CDT - reformat - WDR]
Pl refer to my program:
FORCE=zeros(100,2);
force=zeros(100,2);
for i=1:1:100
m=[H11(i);H21(i)];
n=[H12(i);H22(i)];
frf=[m n];
ffa=[ffa8N(i);ffa10(i)];
FORCE(i,:)=((pinv(frf))*ffa)';
end
force=ifft(FORCE);
force1 =abs(force)*2*pi;
The size of each H11, H12, H21 & H22 is 100x1. I am expecting for each 'i', size of m & n as 2x1, frf as 2x2, ffa as 2x1 and FORCE as 100x2 after transpose. But after the execution I am getting the values for m as [0.187360711350596 - 0.187368466530122i;0.062364375280542 - 0.071296744823281i], and n =[0.208682881606008 + 0.032714463326169i;0.075214194977190 + 0.006696042485398i], ffa =[0.049257402925950 + 0.171256267255695i;-0.068058800649110 + 0.194757769808916i] and frf as [0.187360711350596 - 0.187368466530122i,0.208682881606008 + 0.032714463326169i;0.062364375280542 - 0.071296744823281i,0.075214194977190 + 0.006696042485398i]
I am sure there is some serious mistake in the program. I sincerely request you to kindly help me in locating the logical mistake.
Shrinivas Gombi
1 Kommentar
bym
am 15 Jul. 2011
I don't understand; the sizes you are expecting are the sizes you are getting. m,n,ffa are all 2x1 and frf is 2x2. they are just complex valued
Antworten (0)
Siehe auch
Kategorien
Mehr zu Startup and Shutdown finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!