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heres my code.... getting an error ? Error using ==> horzcat CAT arguments dimensions are not consistent. Error in ==> practice at 3 result=[x(:),y(:),h(:)]; please help????????

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h=double(imread('evening.jpg'));
[x,y]=meshgrid(1:size(h,1), 1:size(h,2));
result=[x(:),y(:),h(:)];

Antworten (2)

Anuj
Anuj am 28 Jan. 2014
The number of rows in x,y,h are not same, so they cannot be concatenated. check your matrix dimensions.
  1 Kommentar
Prasad
Prasad am 28 Jan. 2014
sorry.. but im completely new to matlab. can u pls help me out finding the co ordinates of an image. my ultimate aim is to perform skewing!!!

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Image Analyst
Image Analyst am 28 Jan. 2014
Bearbeitet: Image Analyst am 28 Jan. 2014
Why? You don't need to do that (call meshgrid). You don't need to get the row, column coordinate of every single pixel in your image. Why not just call imtransform() to do skewing? By the way, you didn't even call it correctly. You mixed up x and y with rows and columns. x is columns, not rows and not gotten from size(h, 1).
  2 Kommentare
Prasad
Prasad am 28 Jan. 2014
Bearbeitet: Prasad am 28 Jan. 2014
ohh.. thanx. i would be very grateful if u could provide me with a sample code werin imtransform() has been utilized to perform skewing... thank you in advance!!!
Image Analyst
Image Analyst am 28 Jan. 2014
Did you look at it yet? Don't you want what they call shear in their first example in the help?
I = imread('cameraman.tif');
tform = maketform('affine',[1 0 0; .5 1 0; 0 0 1]);
J = imtransform(I,tform);
imshow(I), figure, imshow(J)

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