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how to plot many plots at the same one?

4 Ansichten (letzte 30 Tage)
mika
mika am 13 Jan. 2014
Hello,
I'm tying to show the result (five plots for detected patterns) of the code below in one plot but in vain,
any idea please
help is much appreciated
n = 50 ;
A = double( rand(n, n+1) > 0.5 ) ;
B = 2*A - 1 ;
patterns = {[1 0 1; 0 1 0; 1 0 1]; ... % X
[1 0 1; 0 1 0; 1 0 0]; ... % Y
[0 1 0; 1 0 1; 0 1 0]; ... % O
[0 0 0; 1 1 1; 0 0 0]; ... % -
[1 0 0; 1 0 0; 1 1 1]} ; % L
labels = {'X', 'Y', 'O', '-', 'L'} ;
matches = cell( size(labels )) ;
for pId = 1 : numel( patterns )
nel = numel( patterns{pId} ) ;
ker = 2*patterns{pId} - 1 ;
[r, c] = find( conv2(B, rot90(rot90(ker)), 'same') == nel ) ;
matches{pId} = [r, c] ;
figure(pId) ; clf ; hold on ;
spy(A) ;
plot( c, r, 'r+', 'MarkerSize', 20 ) ;
title( sprintf( 'Matches for "%s" pattern', labels{pId} )) ;
set( gcf, 'Units', 'normalized' ) ;
set( gcf, 'Position', [0 0 0.4 0.7] ) ;
end

Akzeptierte Antwort

Image Analyst
Image Analyst am 13 Jan. 2014
Bearbeitet: Image Analyst am 13 Jan. 2014
Try using subplot() and getting rid of the set()s:
n = 50;
A = double( rand(n, n+1) > 0.5 ) ;
B = 2*A - 1 ;
patterns = {[1 0 1; 0 1 0; 1 0 1]; ... % X
[1 0 1; 0 1 0; 1 0 0]; ... % Y
[0 1 0; 1 0 1; 0 1 0]; ... % O
[0 0 0; 1 1 1; 0 0 0]; ... % -
[1 0 0; 1 0 0; 1 1 1]} ; % L
labels = {'X', 'Y', 'O', '-', 'L'} ;
matches = cell( size(labels )) ;
for pId = 1 : numel( patterns )
subplot(2,3,pId); % Put plot into this location.
nel = numel( patterns{pId} ) ;
ker = 2*patterns{pId} - 1 ;
[r, c] = find( conv2(B, rot90(rot90(ker)), 'same') == nel ) ;
matches{pId} = [r, c] ;
% figure(pId) ; clf ;
hold on ;
spy(A) ;
plot( c, r, 'r+', 'MarkerSize', 20 ) ;
title( sprintf( 'Matches for "%s" pattern', labels{pId} )) ;
% set( gca, 'Units', 'normalized' ) ;
% set( gca, 'Position', [0 0 0.4 0.7] ) ;
end
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
  2 Kommentare
mika
mika am 15 Jan. 2014
Thank you for your fast reply,
i'm trying to show the result of the shape recognition of 5 patterns at the same plot wich is only one plot. not the five plot at one using subplot.
any idea
thank you
Image Analyst
Image Analyst am 15 Jan. 2014
Try this:
n = 50;
A = double( rand(n, n+1) > 0.5 ) ;
B = 2*A - 1 ;
patterns = {[1 0 1; 0 1 0; 1 0 1]; ... % X
[1 0 1; 0 1 0; 1 0 0]; ... % Y
[0 1 0; 1 0 1; 0 1 0]; ... % O
[0 0 0; 1 1 1; 0 0 0]; ... % -
[1 0 0; 1 0 0; 1 1 1]} ; % L
labels = {'X', 'Y', 'O', '-', 'L'} ;
for pId = 1 : numel( patterns )
nel = numel( patterns{pId} ) ;
ker = 2*patterns{pId} - 1 ;
[r, c] = find( conv2(B, rot90(rot90(ker)), 'same') == nel ) ;
% Append these r and c to the master list.
if pId == 1
% First one
allR = r;
allC = c;
else
allR = [allR; r(:)];
allC = [allC; c(:)];
end
end
plot(allC, allR, 'r+', 'MarkerSize', 20 ) ;
title( sprintf( 'Matches for "%s" pattern', labels{pId} )) ;
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);

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Bruno Pop-Stefanov
Bruno Pop-Stefanov am 15 Jan. 2014
Hi Mika,
If you want to draw all the patterns in the same figure, you should indeed use hold on, however, by calling figure with a different ID number at each iteration of the loop, you create a new figure for each pattern. Also, you use clf which clears everything that was previously plotted on the current figure. Change your code to the following and that should work:
close all
clear all
clc
n = 50 ;
A = double( rand(n, n+1) > 0.5 ) ;
B = 2*A - 1 ;
patterns = {[1 0 1; 0 1 0; 1 0 1]; ... % X
[1 0 1; 0 1 0; 1 0 0]; ... % Y
[0 1 0; 1 0 1; 0 1 0]; ... % O
[0 0 0; 1 1 1; 0 0 0]; ... % -
[1 0 0; 1 0 0; 1 1 1]} ; % L
labels = {'X', 'Y', 'O', '-', 'L'} ;
matches = cell( size(labels )) ;
for pId = 1 : numel( patterns )
nel = numel( patterns{pId} ) ;
ker = 2*patterns{pId} - 1 ;
[r, c] = find( conv2(B, rot90(rot90(ker)), 'same') == nel ) ;
matches{pId} = [r, c] ;
figure(1) ; hold on ;
spy(A) ;
plot( c, r, 'r+', 'MarkerSize', 20 ) ;
title( sprintf( 'Matches for "%s" pattern', labels{pId} )) ;
set( gcf, 'Units', 'normalized' ) ;
set( gcf, 'Position', [0 0 0.4 0.7] ) ;
end

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