Generating integer random numbers from power-law distribution

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Is there a code to generate integer random numbers through power-law distribution of the form p(x)=x^-(alpha+1)?
thanks in advance

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Image Analyst
Image Analyst am 13 Dez. 2013
Try this: RANDRAW

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Miguel Ángel
Miguel Ángel am 13 Dez. 2013
Bearbeitet: Miguel Ángel am 13 Dez. 2013
I don't know if round,ceil or floor is correct, but in case this may be a way
n=1000;
p=rand(1,n);
alpha=0.1;
%inverse of distribution
%properties of logs %LOGa(n) = LOGb(N) / LOGb(a)
%~round/ceil/floor
x=round(log(p)/log(alpha+1));
  1 Kommentar
Sunstar
Sunstar am 13 Dez. 2013
Thank you for your reply. Unfortunately, I cannot simply round or floor or ceil. I need to generate real integers.

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Roger Stafford
Roger Stafford am 13 Dez. 2013
The distribution you mention is equivalent to the zeta distribution with alpha+1 replaced by s. See the website
http://en.wikipedia.org/wiki/Zeta_distribution
As Image Analyst has mentioned, there is a File Exchange contribution called 'randraw' which is located at:
http://www.mathworks.com/matlabcentral/fileexchange/7309-randraw
which claims to generate random numbers in accordance with fifty various distributions including the zeta distribution. It might be what you need.

Weijia Chen
Weijia Chen am 18 Sep. 2019
I also meet the same problem. The minimum integer that zeta distribution can generate seems to be 1, but I hope 0 can be generated. Is there any other distributin can do this? Thank you

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