Find the maximum value and its location from a matrix using two nested loops

13 Ansichten (letzte 30 Tage)
Hi,
Right now I have this matrix K
K =
-3 -8 6 -3 -8 6 9 24 -18
-5 10 -9 -5 10 -9 15 -30 27
8 4 9 8 4 9 -24 -12 -27
-9 -24 18 12 32 -24 3 8 -6
-15 30 -27 20 -40 36 5 -10 9
24 12 27 -32 -16 -36 -8 -4 -9
9 24 -18 -15 -40 30 0 0 0
15 -30 27 -25 50 -45 0 0 0
-24 -12 -27 40 20 45 0 0 0
I wonder how I can use two nested loops to find the maximum number and its location from this matrix.
It would be great if anyone can help me with this
Thank you very much :)

Akzeptierte Antwort

sixwwwwww
sixwwwwww am 8 Dez. 2013
Bearbeitet: sixwwwwww am 8 Dez. 2013
you can do it as follow:
MaxValue = -Inf;
row = 0;
column = 0;
for i = 1:size(K, 1)
for j = 1:size(K, 2)
if K(i, j) > MaxValue
MaxValue = K(i, j);
row = i;
column = j;
end
end
end
  6 Kommentare
Image Analyst
Image Analyst am 8 Dez. 2013
But you didn't ask for other ways - you rigidly specified the way. The other, more MATLAB-ish way would be to use the max() function. Look at the two arguments it returns. You might also find ind2sub() helpful,
Alexandra Vaupotic
Alexandra Vaupotic am 8 Feb. 2021
Bearbeitet: Alexandra Vaupotic am 8 Feb. 2021
How could you make this a function with an output of the Max value?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Khalid Mojallid
Khalid Mojallid am 26 Mär. 2019
MaxValue = -Inf;
row = 0;
column = 0;
for i = 1:size(K, 1)
for j = 1:size(K, 2)
if K(i, j) > MaxValue
MaxValue = K(i, j);
row = i;
column = j;
end
end
end

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Tags

Noch keine Tags eingegeben.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by