How do i count the no of ones of 3D matrix?
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ting
am 22 Nov. 2013
Kommentiert: ting
am 23 Nov. 2013
- I have a big 3-D matrix, say 272*272*272, but contains either 0 or 1; how do i count the number of ones?
- In my project, i need to form a 8*8*8 cube (that why i choose the matrix is 272*272*272). How can i cut this big matrix into 8*8*8 and assign a index for every cube(8*8*8)?
2 Kommentare
Image Analyst
am 22 Nov. 2013
Why do you need an index? What's wrong with the x,y,z value of the center? What are you going to do? Would you like to use blockproc()?
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Azzi Abdelmalek
am 22 Nov. 2013
Bearbeitet: Azzi Abdelmalek
am 22 Nov. 2013
If A is your array
no1=sum(A(:))
For second question
A=rand(272,272,272);
idx2=8:8:272;
idx1=[1 idx2(1:end-1)+1];
n=numel(idx1);
[ii,jj,hh]=ndgrid(1:n,1:n,1:n);
out=arrayfun(@(x,y,z) A(idx1(x):idx2(x),idx1(y):idx2(y),idx1(z):idx2(z)),ii,jj,hh,'un',0);
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