Perform Simple 2-D Translation Transformation
This example shows how to perform a simple affine transformation called a translation. In a translation, you shift an image in coordinate space by adding a specified value to the x- and y-coordinates. (You can also use the
imtranslate function to perform translation.)
Read the image to be transformed. This example creates a checkerboard image using the
cb = checkerboard; imshow(cb)
Get spatial referencing information about the image. This information is useful when you want to display the result of the transformation.
cb_ref = imref2d(size(cb))
cb_ref = imref2d with properties: XWorldLimits: [0.5000 80.5000] YWorldLimits: [0.5000 80.5000] ImageSize: [80 80] PixelExtentInWorldX: 1 PixelExtentInWorldY: 1 ImageExtentInWorldX: 80 ImageExtentInWorldY: 80 XIntrinsicLimits: [0.5000 80.5000] YIntrinsicLimits: [0.5000 80.5000]
Create a 3-by-3 transformation matrix, called
T in this example, that defines the transformation. In this matrix,
T(3,1) specifies the number of pixels to shift the image in the horizontal direction and
T(3,2) specifies the number of pixels to shift the image in the vertical direction.
T = [1 0 0; 0 1 0; 20 30 1]
T = 3×3 1 0 0 0 1 0 20 30 1
Create a geometric transformation object that defines the translation you want to perform. Because translation transformations are a special case of the affine transformation, the example uses an
affine2d geometric transformation object to represent translation. Create an
affine2d object by passing the 3-by-3 transformation matrix,
T, to the
tform = affine2d(T);
Perform the transformation. Call the
imwarp function specifying the image you want to transform and the geometric transformation object.
imwarp returns the transformed image,
cb_translated. This example also returns the optional spatial referencing object,
cb_translated_ref, which contains spatial referencing information about the transformed image.
[cb_translated,cb_translated_ref] = imwarp(cb,tform);
View the original and the transformed image side-by-side using the
subplot function in conjunction with
imshow . When viewing the translated image, it might appear that the transformation had no effect. The transformed image looks identical to the original image. The reason that no change is apparent in the visualization is because
imwarp sizes the output image to be just large enough to contain the entire transformed image but not the entire output coordinate space. Notice, however, that the coordinate values have been changed by the transformation.
figure; subplot(1,2,1); imshow(cb,cb_ref); subplot(1,2,2); imshow(cb_translated,cb_translated_ref)
To see the entirety of the transformed image in the same relation to the origin of the coordinate space as the original image, use
imwarp with the
'OutputView' parameter, specifying a spatial referencing object. The spatial referencing object specifies the size of the output image and how much of the output coordinate space is included in the output image. To do this, the example makes a copy of the spatial referencing object associated with the original image and modifies the world coordinate limits to accommodate the full size of the transformed image. The example sets the limits of the output image in world coordinates to include the origin from the input
cb_translated_ref = cb_ref; cb_translated_ref.XWorldLimits(2) = cb_translated_ref.XWorldLimits(2)+20; cb_translated_ref.YWorldLimits(2) = cb_translated_ref.YWorldLimits(2)+20; [cb_translated,cb_translated_ref] = imwarp(cb,tform,'OutputView',cb_translated_ref); figure, subplot(1,2,1); imshow(cb,cb_ref); subplot(1,2,2); imshow(cb_translated,cb_translated_ref)