![photo](/responsive_image/150/150/0/0/0/cache/matlabcentral/profiles/8201065_1524665118351_DEF.jpg)
Eduardo Santos
Followers: 0 Following: 0
Statistik
7 Fragen
0 Antworten
RANG
212.834
of 297.080
REPUTATION
0
BEITRÄGE
7 Fragen
0 Antworten
ANTWORTZUSTIMMUNG
71.43%
ERHALTENE STIMMEN
0
RANG
of 20.424
REPUTATION
N/A
DURCHSCHNITTLICHE BEWERTUNG
0.00
BEITRÄGE
0 Dateien
DOWNLOADS
0
ALL TIME DOWNLOADS
0
RANG
of 157.776
BEITRÄGE
0 Probleme
0 Lösungen
PUNKTESTAND
0
ANZAHL DER ABZEICHEN
0
BEITRÄGE
0 Beiträge
BEITRÄGE
0 Öffentlich Kanäle
DURCHSCHNITTLICHE BEWERTUNG
BEITRÄGE
0 Highlights
DURCHSCHNITTLICHE ANZAHL DER LIKES
Feeds
Frage
Plot over time milliseconds
I'm trying to plot a number over time. The idea is to show on X-axis the date with milliseconds format. The code below is not w...
mehr als 5 Jahre vor | 1 Antwort | 0
1
AntwortFrage
Subplot UIAxes app designer
I saw the same question here but id doesn`t work (matlab documentation) app.UIFigure.AutoResizeChildren = 'off'; ax1 = subplot...
fast 6 Jahre vor | 1 Antwort | 0
1
AntwortFrage
How change Image/2d array proportions?
Let`s say that I have a image (100x500) (a simple 2D-array) But I know that this image has a real-world size as 25.4 cm heigh a...
fast 6 Jahre vor | 1 Antwort | 0
1
AntwortFrage
1D array to 2D array positions
I would like to 'convert' a 1D array to a 2D matrix considering the value inside the array as: A = 1 3 4 4 ...
fast 6 Jahre vor | 1 Antwort | 0
1
AntwortFrage
1D array values to 2D matrix
I would like to 'convert' a 1D array to a 2D matrix considering the value inside the array as: A = 1 3 5 4 ...
fast 6 Jahre vor | 1 Antwort | 0
1
AntwortFrage
What is the diferrence between finddelay vs dtw functions?
What is the diferrence between finddelay() and dtw(). How can I interpret the information from dtw? I`m using finddelay to g...
etwa 6 Jahre vor | 0 Antworten | 0
0
AntwortenFrage
1D series to 2D stacked
Hi, I`m trying to think in a best option to "convert" a 1d arrays to a 2d as follows: B has a fixed size of 10000x(a prior k...
etwa 6 Jahre vor | 2 Antworten | 0