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Ariela Glikman


Aktiv seit 2018

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number of appearnces of each digit
hi, i have to drew a bar of the number of appearances of each digit. The X label should be the numerical digit and the Y labe...

mehr als 5 Jahre vor | 0 Antworten | 0

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error using the cellfun function
Hi guys,I have a cell with names (first.last) and I wrote a function who receives names and checking if they are written correct...

mehr als 5 Jahre vor | 1 Antwort | 0

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convert cell in minutes to seconds vector
hi, i have the cell time = {[3,41] [2,59] [3,12] [5,27]} ie : [2 30] is 2.5 minutes, and i need the time in secounds. ...

mehr als 5 Jahre vor | 1 Antwort | 0

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cell of minutes and seconds
hi, i have cell of minutes and seconds, and i need it on minutes. the cell is: time= {[3,41] [2,59] [3,12] [5,27]} ie: [...

mehr als 5 Jahre vor | 1 Antwort | 0

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sorting skalars and string
hi, i have cell array with strings and skalars name : 'hun.mat' this is the cell: hun= {'chocolate',40,'strawberry jam',50,'...

fast 6 Jahre vor | 1 Antwort | 0

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random vector (1,10)
hi, im tring to make a vector size (1,10) who has random integers between 1 to a, ( but only round numbers ) v= a-1 .* r...

fast 6 Jahre vor | 2 Antworten | 0

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flip a matrix using loops
hi, im tring to flip a matrix usind withot the flip function for ex: [1 3 -2; -4 4 8; 7 -1 3] will cange to [7 -1 3; -4 ...

fast 6 Jahre vor | 2 Antworten | 0

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sum all columns in a matrix
hi, i want to sum all the columns of some matrix. but without using a loop or the sum function. for ex: for the matrix [1...

fast 6 Jahre vor | 2 Antworten | 0

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hey how can i make column output?
hey how can i make column output? (and not row vec) % the function gets a vector of numbers (=vecOfNum) % and return output v...

etwa 6 Jahre vor | 1 Antwort | 0

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cumulative average for each element
hey, i need to build a function who receives a vector and return the cumulative average for each element . for ex: vecMean([1...

etwa 6 Jahre vor | 2 Antworten | 0

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hi, im tring to make a new vector from some exics one.
grades= [87 81 87 80 94 87 62]; scholarship=[]; for i=i:length(grades) if (grades (i)>85) scholarship(i)=grad...

etwa 6 Jahre vor | 2 Antworten | 0

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