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How to calculate the length of the longest crack in this image automatically ?
How to highlight those cracks in this image and calculate their lengths?
3 Monate vor | 1 Antwort | 0
1
AntwortFrage
How can I calculate three different shaded areas?
I have three groups of sample points as attached, and intend to calculate three different shaded areas under curve from x = -40 ...
6 Monate vor | 1 Antwort | 0
1
AntwortFrage
How can I calculate the shaded area ?
I have a representative subset of sample points as attached, and intend to calculate the shaded area from x = -40 to x = 30.
6 Monate vor | 1 Antwort | 0
1
AntwortFrage
How can I add query points between two adjacent points of sampled data？
I have a representative subset of sample points as shown in column A (x), and intend to add query points (evenly) in interval ...
etwa ein Jahr vor | 1 Antwort | 0
1
AntwortFrage
How can I add query points between two adjacent points of sampled data and perform interpolation?
I have a representative subset of sample points as shown above, and intend to define the query points to be a finer sampling o...
etwa ein Jahr vor | 1 Antwort | 0
1
AntwortFrage
How can I retrieve those elements by their positions in a matrix?
I have a matrix example as shown above, and the data in column A, D, G share the same row index. In column B, E, H, there are ...
etwa ein Jahr vor | 1 Antwort | 0
1
AntwortFrage
How can I multiply a row vector with each of two column vectors?
I have a row vector and two column vectors, and intend to perform their multiplication (element by element). The following is an...
etwa ein Jahr vor | 1 Antwort | 0
1
AntwortFrage
How can I multiply a row vector with each of two column vectors?
I have a row vector and two column vectors, and intend to perform their multiplication (element by element). The following is an...
etwa ein Jahr vor | 2 Antworten | 0
2
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How can I calculate the grouped data?
I have some grouped data, and intend to perform an element-wise squaring one by one and find out the minimum of calculated resul...
etwa ein Jahr vor | 1 Antwort | 0
