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For-loop instantly jump to largest value
Your for loop construct itself is incorrect. It should be for rpm1 = a:b:c where a and c are start and end limits and b ...
fast 7 Jahre vor | 0
how to plot output voltage graph of 6-pulse rectifier?
Simply use hold on command to hold the 6 plots on to the same figure. e.g hold on plot(y1); plot(y2); % and so on.
fast 7 Jahre vor | 0
I am getting error for Q
Firstly, as far as the error is concerned, *to access any element of an array, its index has to be an integer, not a real number...
fast 7 Jahre vor | 0
How to time-match measurements for two time series?
You can correlate the two data to find out the index of the correlation peak. Later, you can use this index to shift the indices...
fast 7 Jahre vor | 0
universal control unit serial port connection
Use instrfind() function to find out the status of the current port that you want to connect to. That will do.
fast 7 Jahre vor | 0
How can I separate a signal of same frequency but different amplitude?
The signal samples in the image looks like they are time-domain multiplexed.Try this x1 = x(1:2:end) and x2 = x(2:2:end). Don't ...
fast 7 Jahre vor | 0
how to filter EEG excel data(2562*11) using matlab.
There is no need to use any for loops. Just use colon operator to extract a particular column from the matrix (formed after impo...
fast 7 Jahre vor | 0
How to determine the distance at which two vectors intersect having their origins and their directions
You can make use of the function find() on their difference vector. That should do it.
fast 7 Jahre vor | 0
Matlab help with discrete time signal
since your sequence is { ka,ka^2,ka^3,ka^4} which is {x(1) x(2) x(3) x(4) } and the sequence weights are known. hence your a= x(...
etwa 12 Jahre vor | 0
Putting Three different functions into one program
if the functions are just based on some formulae , i mean for example it may be f(x)= some trigonometric formulae/expressions , ...
etwa 12 Jahre vor | 0
command window data
1. If you have defined a function/looping structures for your code then all the variables will be local to that particular funct...
etwa 12 Jahre vor | 0
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Comparing two vectors with different dimensions
Let a and b be two arrays(or vectors). L=length(a), M=length(b).Suppose L>M, pad_zero=L-M; now b=[b zeros(1,pad_zero)]; c=a-b; ...
etwa 12 Jahre vor | 0