Aramis

Last seen: 6 Monate vor | Aktiv seit 2024

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how to find the element which is greater than or equal to its row and smaller or equal to its column in a matrix
The best solution function s = saddle(M) % Create logical vector that are true for each saddle condition separately m...

mehr als ein Jahr vor | 0

Beantwortet
Sparse Matrix, struct, structure, Using cell arrays
function matrix = sparse2matrix(cellvec) matrix = ones(cellvec{1}) * cellvec{2}; for x=3:length(cellvec) matr...

mehr als ein Jahr vor | 0

Beantwortet
next prime number using While loops
THE BEST ANSWER function k = next_prime(n) k=n; while isprime(k)==false || k==n k = k+1; end end ...

fast 2 Jahre vor | 0

Beantwortet
Write a function called valid_date that takes three positive integer scalar inputs year, month, day. If these three represent a valid date, return a logical true, otherwise false. The name of the output argument is valid.
The best answer function valid = valid_date(year,month,day) if not(isscalar(year))|| not(isscalar(month)) || not(isscalar(...

fast 2 Jahre vor | 1

Beantwortet
Write a function called eligible that helps the admission officer of the Graduate School decide whether the applicant is eligible for admission based on GRE scores. The function takes two positive scalars called v and q as in
This is the BEST FCKN ANSWER function admit = eligible(v, q) admit = mean([v q]) >= 92 && min([v q]) > 88; end

fast 2 Jahre vor | 2

Beantwortet
Write a function called minimax that takes M, a matrix input argument and returns mmr, a row vector containing the absolute values of the difference between the maximum and minimum valued elements in each row. As a second output argument called mmm,
function [x, y] = minimax(M) x = (max(M,[],2) - min(M,[],2))'; y = max(M,[], "all")- min(M,[], "all"); end

fast 2 Jahre vor | 0