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How to smooth or clear the peak of the curve at certain time level?
This is the tridaigonal system. here, i incoparate the time steps and it will stop at tolerance limit. and then i got the datas ...
etwa ein Jahr vor | 1 Antwort | 0
1
AntwortFrage
How to use iteration and error for crank nicolson type to converge spatial and temporal discretization?
I'm using iteration and error for spatial discretization and temporal discretization respectively. I want apply iteration and er...
mehr als 2 Jahre vor | 1 Antwort | 0
1
AntwortFrage
How to obtain convergence of the curve to my boundary condtion?
I want a curve in each 'j'th iteration. But, I didn't get convergence of the curve to plot each 'j'th iterations between limit 1...
mehr als 2 Jahre vor | 1 Antwort | 0
1
AntwortFrage
How to stop time loop when steady state is reached?
I'm using unsteady case. so, it will reach a steady state at a certain time level. I fixed time at 'j'th column wise and it ran ...
mehr als 2 Jahre vor | 1 Antwort | 0
1
AntwortFrage
What is the steady state criteria in crank nicolson scheme, especially impilicit finite difference method? and How to stop time level when steady state is reached?
I'm dealing with unsteady case in my code. so, the CN term updated in each time step and it ran upto final time (tmax=100). but ...
fast 3 Jahre vor | 1 Antwort | 0
1
AntwortFrage
How to use indices in A matrix while conditonal and for loop condtion?
How to use indices in LHS of A matrix while using for and if, esleif and else condtions? clc clear all m=5;n=7; A=zeros(m,m)...
fast 3 Jahre vor | 2 Antworten | 0
2
AntwortenFrage
How to change diagonal, subdiagonal and superdiagonal values with respect time while using loop and conditional statement?
xmax=1; ymax=7; m=20; n=29; dx=xmax/m; dy=ymax/n; dt=0.2; UOLD=zeros(m,n);VOLD=zeros(m,n); A=zeros([1,m]); B=A; C=A; whi...
fast 3 Jahre vor | 2 Antworten | 0
2
AntwortenFrage
How to describe right hand side of energy equation in tridiagonal system? Didn't get right hand side values of tridiagonal matrix.
xmax=1; ymax=20; dx=0.05; dy=0.25; dt=0.02; m=xmax/dx; n=ymax/dy; U=zeros(m,n); V=zeros(m,n); for j =1:n D(i)=-U(i,j)*...
etwa 3 Jahre vor | 1 Antwort | 0
1
AntwortFrage
There is a mistake while using condtional and for loop condtion.i got the value zero only. but i want values and here, A is subdiagonal, B is diagonal and C is superdiagonal.
xmax=1; ymax=20; dx=0.05; dy=0.25; dt=0.02;m=xmax/dx; n=ymax/dy; UOLD=zeros(m,n); VOLD=zeros(m,n); for j=1:n if i==2:m...
etwa 3 Jahre vor | 1 Antwort | 0
1
AntwortFrage
here, i couldn't get the A,B,C values while using if, elseif conditions. how to get values while using conditional statement?
dx=0.05; dy=0.25; dt=0.2; for j=1:n if i==2:m C(i)=V(i,j)*dt/4*dy-dt/2*(dy)^2; elseif i==1:m-1 A(i)...
etwa 3 Jahre vor | 1 Antwort | 0
