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S C.Carl


Last seen: etwa ein Jahr vor |  Aktiv seit 2016

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Why does imshow display different image when I try to show a CT image?
Thanks for your response. However, your codes still show binary result rather than a grayscale result :( Our images are attach...

etwa ein Jahr vor | 0

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Why does imshow display different image when I try to show a CT image?
Hi, I want to show an original abdominal CT (Computed Tomography) image (which is uint16 bit ) with these codes; im = imread('...

etwa ein Jahr vor | 2 Antworten | 0

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Quantitative evaluation of the images generated by GAN
Hi, I run the codes at https://www.mathworks.com/help/deeplearning/ug/train-generative-adversarial-network.html and want to ev...

mehr als ein Jahr vor | 0 Antworten | 0

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Images obtained by GAN could not be shown
Hi, I run the codes at https://www.mathworks.com/help/deeplearning/ug/train-generative-adversarial-network.html which generates...

etwa 2 Jahre vor | 1 Antwort | 0

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Creating .mat from images
I want to run the following codes. load('DatasColor_38.mat','DATA'); % to load the dataset % the information to split data be...

etwa 2 Jahre vor | 0 Antworten | 0

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How to get colormap of a non-indexed RGB image?
I have an RGBImage (but not an indexed image). I applied a denoising operation of its grayscale image and obtained a DenoisedI...

mehr als 2 Jahre vor | 1 Antwort | 0

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bar graph : How to show each bar with different base value ?
Thanks for your response But, I could not solve my problem. My goal is to show each data pair in y1 and y2 at different base...

etwa 6 Jahre vor | 0

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If you want to determine noise type with kurtosis, skewness, do you calculate from background (since foregrounds may include tumors) ???
Hi, I want to evaluate kurtosis and skewness features of images. I want to calculate kurtosis and skewness to determine th...

mehr als 7 Jahre vor | 0 Antworten | 0

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how can a matlab code be written for identification of noise using statistical features like kurtosis and skewness?
I have the same question. How to identify noise in an image ? Dear Image Anaylst, could you please send me the application ...

etwa 8 Jahre vor | 0

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bar graph : How to show each bar with different base value ?
Hi, I would like to show use bar graph. But each bar has different base line. So, I wrote the following codes. However,...

etwa 8 Jahre vor | 3 Antworten | 0

3

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similarity of binary images
There are two results (binary vessel images) obtained from two different methods. They appear very close (almost the same). ...

mehr als 8 Jahre vor | 0 Antworten | 0

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RGB colored image segmentation
Hi all, I have an RGB colored histology slide. I am getting blue and green components in this image by, imgG=IMG(:,:,2); ...

mehr als 8 Jahre vor | 2 Antworten | 0

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A function to find peaks (brightest pixels in a grayscale image) ?
Hi, Is there any function as an alternative to FastPeakFind() to find brightest pixels in a grayscale image. The problem o...

mehr als 8 Jahre vor | 1 Antwort | 0

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Why are these codes NOT giving 4 biggest connected component in the stack image ???
I added these codes, but the result does not changed; for slice=1:7 if temp77(:,:,slice)==k2 biggestPart = t...

mehr als 8 Jahre vor | 0

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Why are these codes NOT giving 4 biggest connected component in the stack image ???
Hi, I need your help. I have a tiff image that includes 7 slices. I want to find 4 biggest connected component in the tiff ...

mehr als 8 Jahre vor | 2 Antworten | 0

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How to read a tiff image (3D) that includes 2D images ? (imread gives only the first image)
I used the following codes to reconstruct a 3D image that includes 2D slices for slice = 1 : numberOfSlices filename = spri...

mehr als 8 Jahre vor | 2 Antworten | 0

2

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Beantwortet
Loading, Processing and Analysing 3-D Images
Hi, I have a similar problem but could not solve it. I used the following codes to reconstruct a 3D image that includes 2D s...

mehr als 8 Jahre vor | 0

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How to assign zero value to plotted lines
Hi, I have the following codes to plot lines on an image. I want to assign zero value to the lines plotted by the following c...

mehr als 8 Jahre vor | 1 Antwort | 0

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