Statistik
7 Fragen
0 Antworten
RANG
94.964
of 292.728
REPUTATION
0
BEITRÄGE
7 Fragen
0 Antworten
ANTWORTZUSTIMMUNG
42.86%
ERHALTENE STIMMEN
0
RANG
of 19.934
REPUTATION
N/A
DURCHSCHNITTLICHE BEWERTUNG
0.00
BEITRÄGE
0 Dateien
DOWNLOADS
0
ALL TIME DOWNLOADS
0
RANG
of 147.895
BEITRÄGE
0 Probleme
0 Lösungen
PUNKTESTAND
0
ANZAHL DER ABZEICHEN
0
BEITRÄGE
0 Beiträge
BEITRÄGE
0 Öffentlich Kanäle
DURCHSCHNITTLICHE BEWERTUNG
BEITRÄGE
0 Highlights
DURCHSCHNITTLICHE ANZAHL DER LIKES
Feeds
Frage
In the following Simulink model why am I getting a double step at the transition from one step to the next?
dplla5.slx
mehr als 9 Jahre vor | 0 Antworten | 0
0
AntwortenFrage
probability of a run of k heads or more in N tosses of a fair coin N>>k
is there a code for this. One solution is given in http://www.drdobbs.com/architecture-and-design/20-heads-in-a-row-what-are-t...
mehr als 10 Jahre vor | 3 Antworten | 0
3
AntwortenFrage
program behavior due to editor issues
In the attached code adding the two line commands near the top changes the behavior of the program from how it behaved without t...
fast 11 Jahre vor | 0 Antworten | 0
0
AntwortenFrage
breaking an if loop
In the following script, why doesn't the break in line 24 get executed? clf xx = 1:.01:2; vec = 1:.01:2; for i=1:10...
fast 11 Jahre vor | 3 Antworten | 0
3
AntwortenFrage
In the following script, shifting the % symbols to the line below where they are shown givies different results. The version shown below gives the correct result. The versison with the % signs moved gives an incorrect result. Any ideas?
% trajetory 1 clf xx=1:10;y=[1 0 0 0 0 0 0 0 1 0];stem(xx,y) hold on m = .1; xz(1) = 11; y(1) = 1.1; f...
fast 11 Jahre vor | 1 Antwort | 0
1
AntwortFrage
what is wrong with the following code. I should have sent the full script. Sorry. On my macine the vector 'x' ranges from 0 to 10.1
% trajetory 1 clf m = .1; %n = .2; % xx=1:10;y=[1 0 0 0 0 0 0 0 1 0];stem(xx,y) %hold on x(1...
fast 11 Jahre vor | 1 Antwort | 0
1
AntwortFrage
What is wrong with the following script?
x(1) = 0; i = 1; y(1) = 1.1; while x(i) <= 1.0 %x(i)= i; x(i+1) = x(i) + 0.1; y(i+1) = y(1)...
fast 11 Jahre vor | 2 Antworten | 0