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Sara Nasir


Last seen: 6 Monate vor |  Aktiv seit 2020

Followers: 0   Following: 0

Programming Languages:
MATLAB
Spoken Languages:
English

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Optimize loop to reduce run time
My code works well but it takes a lot of time to run since the vectors are larger in size. I know it can be optimized by using v...

6 Monate vor | 2 Antworten | 0

2

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calculate stop band energy from PSD graph
I want to find the value of the stop band energy i.e. the total leaked energy to the neighbouring sub-carriers. The value is cal...

fast 4 Jahre vor | 0 Antworten | 0

0

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Calculate the stop band energy of a filter by its Power spectral density graph
I want to find the stop band energy of a filter by its Power spectral density graph. Stop band energy is calculated with normali...

fast 4 Jahre vor | 1 Antwort | 0

1

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OFDM implementation in Simulink
I am implementing OFDM Transmitter using QPSK Modulation. I am having trouble adding cyclic prefix to OFDM symbols as there is n...

etwa 4 Jahre vor | 1 Antwort | 0

1

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Tukey window in time domain
I am trying to implement Tukey window in time domain. It is the rectangular filter where the edgesare tapered by convolving a re...

etwa 4 Jahre vor | 0 Antworten | 0

0

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Hanning window Frequency Domain Graph
Hello, I have calculated the time domain of hanning window through the formula. But now I have to find the frequency domai...

etwa 4 Jahre vor | 2 Antworten | 0

2

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Root raised cosine pulse
B=0.5; %Beta value Ts = 0.01; %Sampling interval N=2000; %Number of samples t=-20:Ts:(N-1)*Ts; %Formula pt_RootR...

mehr als 4 Jahre vor | 1 Antwort | 0

1

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Error: Unable to perform assignment because the left and right sides have a different number of elements.
M = 64; %Number of subcarriers K = 4; %Overlapping factor y = [-0.2...

mehr als 4 Jahre vor | 1 Antwort | 0

1

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Matlab Summation equation for calculating impulse response of FBMC
Hello guys, I am trying to solve this equation to calculate the impulse response of a filter bank carrier but the graph is not...

mehr als 4 Jahre vor | 1 Antwort | 0

1

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