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Umar Bhai

Last seen: 6 Monate vor | Aktiv seit 2019

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Consider a signal ?[?] = (0.2)??[?]. plot the magnitude, angle, real and imaginary parts of ?(???). Plot ?(???) at 101 101 equispaced points between 0 and ?. help me to find error in subplot command. all four items are not plotted.
w = [0:1:100]*pi/100; X = exp(j*w) ./ (exp(j*w) - 0.2*ones(1,101));magX = abs (X) ; angX = angle (X) ;realX = real(X); imagX ...

fast 5 Jahre vor | 1 Antwort | 0

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?1(?) = 1 + 2?−1 + 3?−2 and ?2(?) = 4 + 5?−1 + 6?−2. Use MATLAB to generate a sequence ?3(?) = ?1(?)?2(?). Utilize either the multiplication property or the convolution property. send me some other proper code if anyone have
>> x1=[1 2 3]; >> x2=[4 5 6]; >> x3=conv(x1,x2) Output: x3 = 4 13 28 27 18

fast 5 Jahre vor | 0 Antworten | 0

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(input given as ?[?] = {1, 2,3} impulse given as ℎ[?] = {4,5,6} for 0 ≤ ? ≤ 2.) there is an error in my output..in sketching of y[n], we required a discrete in time signal but my output signal is continuous as seen clearly in screenshot below
n = 0:2; x =[1 2 3]; h=[4 5 6]; y=conv(x,h); plot(y) xlabel('time axis'); title('output of a system'); ylabel('y axis')

fast 5 Jahre vor | 1 Antwort | 0

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a) Consider an input of a system given as ?[?] = {1, 2,3} and the impulse response of a system given ↑ as ℎ[?] = {4,5,6} for 0 ≤ ? ≤ 3. Use MATLAB to find and sketch the output ?[?].
Consider an input of a system given as ?[?] = {1, 2,3} and the impulse response of a system given ↑ as ℎ[?] = {4,5,6} for 0 ≤ ...

fast 5 Jahre vor | 1 Antwort | 0

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x(i+1)=y(i)-((f(y(i))/d(y(i)))); // error in this line..
% Program Code of Newton-Raphson Method in MATLAB a=input('Enter the function in the form of variable x:','s'); y(1)=input...

etwa 5 Jahre vor | 1 Antwort | 0

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