teja jayavarapu
Followers: 0 Following: 0
Statistik
RANG
154.901
of 294.421
REPUTATION
0
ANTWORTZUSTIMMUNG
11.11%
ERHALTENE STIMMEN
0
RANG
of 20.110
REPUTATION
N/A
DURCHSCHNITTLICHE BEWERTUNG
0.00
BEITRÄGE
0 Dateien
DOWNLOADS
0
ALL TIME DOWNLOADS
0
RANG
of 151.653
BEITRÄGE
0 Probleme
0 Lösungen
PUNKTESTAND
0
ANZAHL DER ABZEICHEN
0
BEITRÄGE
0 Beiträge
BEITRÄGE
0 Öffentlich Kanäle
DURCHSCHNITTLICHE BEWERTUNG
BEITRÄGE
0 Highlights
DURCHSCHNITTLICHE ANZAHL DER LIKES
Feeds
I am getting more time complexity ,can you possibly minimize the code
disp('query') [filename, pathname]=uigetfile({'*.jpg'},'queryimage'); % This code is for LOCAL COLOUR HISTOGRAM ________...
mehr als 6 Jahre vor | 0
I am getting more time complexity ,can you possibly minimize the code
Are you still getting the same time complexity
mehr als 6 Jahre vor | 0
I am getting more time complexity ,can you possibly minimize the code
I have resized all the images to 256x256 using coverted file below,I think you got all the required information if i am less of ...
mehr als 6 Jahre vor | 0
I am getting more time complexity ,can you possibly minimize the code
can you please find error in my code so i can proceed further.I am unable retrive the images with this code properly
mehr als 6 Jahre vor | 0
Frage
I am getting more time complexity ,can you possibly minimize the code
please review the attached code below,and give me some suggestions to reduce the time complexity
mehr als 6 Jahre vor | 6 Antworten | 0
6
AntwortenI have written a logic for co-occurance matrix but it is taking a lot of time, is there any other to built the logic?
Ok,thank you for the support,can you please help me with the Gussian internal normalisation for texture parameters of (capacity,...
mehr als 6 Jahre vor | 0
Frage
I have written a logic for co-occurance matrix but it is taking a lot of time, is there any other to built the logic?
4.Calculate four co-occurrence matrices P, take the distance 1, the angles are 0, 45, 90, 135 respectively %M&N ARE ROWS &C...
mehr als 6 Jahre vor | 3 Antworten | 0
3
AntwortenFrage
i want to divide into subblocks in 1:2:1 proportion(As in the attached fiures) how do i do that
please let me know if there is any possiblity of using mat2cell for this
mehr als 6 Jahre vor | 0 Antworten | 0
0
AntwortenFrage
how do i divide image into subblocks in 1:2:1 proportion like shown in the figure
please help me with this
mehr als 6 Jahre vor | 1 Antwort | 0
1
Antworti used the below code for image retrival through corel database but my results are not upto the mark,please verify my node and let me get your help to make necessary corrections,I use local color feature
http://wang.ist.psu.edu/docs/related/ This is the related link where the test images are available, I think you can manage to...
mehr als 6 Jahre vor | 0
Frage
i used the below code for image retrival through corel database but my results are not upto the mark,please verify my node and let me get your help to make necessary corrections,I use local color feature
tic disp('query') [filename, pathname]=uigetfile({'*.jpg'},'queryimage'); img=strcat(pathname,filename); a=imread(...
mehr als 6 Jahre vor | 2 Antworten | 0
2
AntwortenFrage
I have an image and I need to extract local features,so I divided it to 16 blocks and size of each block =64 *64 pixels and extract that three color histograms features locally from each block, now I need to
tic disp('query') [filename, pathname]=uigetfile({'*.jpg'},'queryimage'); img=strcat(pathname,filename); a=imread(...
mehr als 6 Jahre vor | 1 Antwort | 0
1
AntwortFrage
I have an image and I need to extract local features,so I divided it to 16 blocks and size of each block =64 *64 pixels and extract that three color histograms features locally from block, how can i do?
tic disp('query') [filename, pathname]=uigetfile({'*.jpg'},'queryimage'); img=strcat(pathname,filename); a=imread(img); sub...
mehr als 6 Jahre vor | 0 Antworten | 0
0
AntwortenFrage
i have divided the image into blocks now, i want to access each block individually and i compute histogram how do i access each block
a=imread(img); subplot(4,3,2) imshow(img) set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0.05 1 0.95]); [r, c...
mehr als 6 Jahre vor | 1 Antwort | 0
1
AntwortI have quantized hsv into 8×3×3 combinations,so I want to find what is number of pixels per each bin how do I do it
a=imread(img); [rows, cols, numOfBands] = size(a); mr=round(rows/2); mc=round(cols/2); image1=a(1:mr,1:mc); image2=a(1:mr,(...
mehr als 6 Jahre vor | 0
I have quantized hsv into 8×3×3 combinations,so I want to find what is number of pixels per each bin how do I do it
If I divide image into N×N blocks how do we apply this quantification for different blocks
mehr als 6 Jahre vor | 0
Frage
I have quantized hsv into 8×3×3 combinations,so I want to find what is number of pixels per each bin how do I do it
h
mehr als 6 Jahre vor | 3 Antworten | 0
3
AntwortenHow to get Color Histogram of an Image
I have quantized hsv into 8×3×3 combinations,so I want to find what is number of pixels per each bin how do I do it
mehr als 6 Jahre vor | 0