You must create a n-by-n symmetric matrix such that A(row,col) = row/col for col >= row.
Example if n =3 :
output is : A =
1.0000 0.5000 0.3333
0.5000 1.0000 0.6667
0.3333 0.6667 1.0000
since A(2,1) = A(1,2) = 1/2
or A(3,1)= A(1,3) = 1/3
Solution Stats
Problem Comments
1 Comment
Solution Comments
Show comments
Loading...
Problem Recent Solvers345
Suggested Problems
-
Sort a list of complex numbers based on far they are from the origin.
5798 Solvers
-
MATCH THE STRINGS (2 CHAR) very easy
301 Solvers
-
568 Solvers
-
Back to basics - mean of corner elements of a matrix
462 Solvers
-
3438 Solvers
More from this Author30
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
In my opinion the caption of the problem "Symmetric matrix" has to be changed because it is too vague. I would suggest something like symmetric matrix with i,j=i/j