Given a collection of points, return the indices of the rows that contain the two points most distant from one another. The input vector p has two columns corresponding to the x and y coordinates of each point. Return ix, the (sorted) pair of indices pointing to the remotest rows. There will always be one unique such pair of points.
So if
p = [0 0]
[1 0]
[2 2]
[0 1]Then
ix = [1 3]
That is, the two points p(1,:) and p(3,:) are farthest apart.
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More easy that it seems.
You need to specify "Euclidean" distance :-)
Good problem, not too hard but required thinking
Please add the next test :
p = [0,0;
2,1;
2,6;
1,6];
ix_correct = [1 3];
assert(isequal(mostDistant(p),ix_correct))
The solutions of the form:
[~,indx]=max(dist(p'));
unique(indx)
will fail, the last line will return an extra index [1,3,4] instead of just [1,3]
refer to
Convex Hull therom and the Graham's Scan method
+1
Nice one!