Problem 62. Elapsed Time
Given two date strings d1 and d2 of the form yyyy/mm/dd HH:MM:SS (assume hours HH is in 24 hour mode), determine how much time, in decimal hours, separates them. Assume d2 is always later than d1.
Example:
Input d1 = '2010/12/14 12:00:00' Input d2 = '2010/12/14 13:06:36' Output elapsed is 1.11
Solution Stats
Problem Comments
-
12 Comments
The testsuite input does not following the input format string.
Having a hard time with the test suite regarding the number of hours in one year. I think it should be 8 765.81277h/y
The test suite doesnt follow. it should be double digit days and month, not single digits according to his descrption
having problems with the test suite especially test no 3
having problems with test no 3 of the test suite,why?
It's a fun problem
the test suits are all passed , but the mathworks net tells its wrong.
and the size is '-1'.
i use the datenum function.
I use format bank to get 2 decimal output, anyone has a better idea?
using existing functions makes this trick easy
with an existing funcion it is solveable
function elapsed= elapsed_time(d1,d2)
d1='2010/12/14 12:00:00'
d2='2010/12/15 13:06:36'
a=(str2num(d2(1:4))-str2num(d1(1:4)))*8760;
b=(str2num(d2(6:7))-str2num(d1(6:7)))*720;
c=(str2num(d2(9:10))-str2num(d1(9:10)))*24;
e=str2num(d2(12:13))-str2num(d1(12:13));
f=(str2num(d2(15:16))-str2num(d1(15:16)))/60;
g=(str2num(d2(18:19))-str2num(d1(18:19)))/3600;
elapsed=a+b+c+e+f+g
end
it told me that solution is wrong?
Nice question
Solution Comments
Show commentsProblem Recent Solvers2911
Suggested Problems
-
Find the peak 3n+1 sequence value
2492 Solvers
-
Determine Whether an array is empty
769 Solvers
-
9437 Solvers
-
511 Solvers
-
Convert a Cell Array into an Array
1656 Solvers
More from this Author96
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!