For a vector or matrix X and an interval [n1,n2], the function replace every element of x inferior to n1 by n1, and every element of x superior to n2 by n2.
x= [1 2 3 4 5 1 2 4 6]
y_correct= [3 3 3 4 5 3 3 4 5]
Back to basics 15 - Benchmark
Convert from Base 10 to base 5
Given a 4x4 matrix, swap the two middle columns
Add a row of zeros on top of a matrix
Create sequnce 1 4 9 16 25.........
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