Consider the recursion relation:
x_n = (x_(n-1)*x_(n-2))^k
Given x_1, x_2, and k, x_n can be found by this definition. Write a function which takes as input arguments x_1, x_2, n and k. The output should be x_n.
For example, if x_1=exp(1), x_2=pi, n=5, and k=5/9 then:
R = get_recurse(exp(1),pi,5,4/9)
R =
2.31187497992966
Solution Stats
Problem Comments
4 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers85
Suggested Problems
-
Find all elements less than 0 or greater than 10 and replace them with NaN
15815 Solvers
-
2183 Solvers
-
190 Solvers
-
Who has power to do everything in this world?
490 Solvers
-
Sum of first n positive integers
630 Solvers
More from this Author6
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
is there a story as to why this is "infernal"?
I hate recursion, so it is all infernal to me! Iteration is the way to go...
Test suite could helpfully include n=1 and n=2 tests. I thought that it needed extra complexity to handle these, but @bmtran's top solution shows it doesn't.
I spend a lot of time to get the correct R from the example. The issue is that you say k = 5/9 instead of 4/9 . Just a typo to correct . Thanks