Given an input vector x, find all elements of x less than 0 or greater than 10 and replace them with NaN.
Example:
Input x = [ 5 17 -20 99 3.4 2 8 -6 ] Output y is [ 5 NaN NaN NaN 3.4 2 8 NaN ]
Solution Stats
Problem Comments
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9 Comments
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6 older comments
James Ross
on 16 Jun 2012
This is a poorly posed problem. There are no numbers that are both less than zero and greater than 10.
Alexander
on 17 Jan 2013
Just had the same thought as James Ross...
Ned Gulley
on 20 Jun 2013
Fixed the wording to reflect this. Thanks for the comments.
ricardo gunawan
on 14 Jul 2013
come on wth is this problem i got wrong when i check my answer is true
Matt Raum
on 20 Aug 2013
Can someone explain this to me?
cleanUp=@(lb,x)interp1([lb 10],[lb 10],x);x=[5 17 -20 99 3.4 2 8 -6];y_correct=[5 NaN NaN NaN 3.4 2 8 NaN];
[isequalwithequalnans(cleanUp(1,x),y_correct),isequalwithequalnans(cleanUp(0,x),y_correct)]
That is, if i set the lower bound (lb) of the interpolation to 1 it passes the test code but if I set it to zero it fails with the same output!?!
Jean-Marie Sainthillier
on 20 Aug 2013
The 3.4 in the result isn't the same in the two interpolations (diff= 4.440892098500626e-16). It's small but it's enough to fail the isequal test.
Felipe
on 30 Apr 2014
16 is the first non-regexp-solution!
Kirti Raikar
on 23 Jun 2015
good question
Thibault Clayeux
on 15 Oct 2015
I have Assertion failure for the first test but it's good for the second --' I don't understand. Can you help me ?
Solution Comments
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1 Comment
Tong Wang
on 19 Oct 2018
this hasn't been fixed?
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1 Comment
Lalit Kumar
on 8 Aug 2018
good
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1 Comment
Caleb Ogline
on 20 Nov 2017
l
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1 Comment
xinyu lei
on 7 Aug 2017
I reduce my code size with the help in this page.
http://matlabtricks.com/post-16/the-background-of-cody-solutions-having-extremely-low-size.
Besides, leading solution is a cheater.
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1 Comment
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
very easy
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1 Comment
Ethan Colaizzi
on 24 Jul 2016
Nicely done!
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2 Comments
Md Sumon
on 19 Jul 2016
How can I make it shorter?
James Tanner
on 26 Jun 2017
You could remove the 1's:
i= 1:length(x)
and
x(i)<0 | x(i)>10
Also, it's probably best to use numel instead of length.
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1 Comment
Giovanni Mottola
on 7 Jun 2016
First non trivial one, learned a new trick
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2 Comments
Md Tariqul Islam
on 23 Nov 2015
Any suggestion on how to reduce the size?
Tanzil Bin Hassan
on 2 Jan 2016
x(x < 0 | x > 10) = NaN // use this it will reduce code size
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3 Comments
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1 Comment
Mohapi Mohlamonyane
on 4 Jun 2014
This is called logical indexing
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1 Comment
Vishal
on 23 Apr 2014
good
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1 Comment
Hussain
on 27 Nov 2013
No need of colon operator...
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6 Comments
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3 older comments
Patricia
on 3 Dec 2013
How does the cleanup function work? I did not find a good explanation, but would be interested in how it works.
Dmitry Kislitsyn
on 14 Jan 2014
I don't understand how this size is possible. Even something as simple as y=x+1; has size 12 according to "About Cody" page! Kind of mystery for me...
Dmitry Kislitsyn
on 14 Jan 2014
So I googled and found an explanation here http://matlabtricks.com/post-16/the-background-of-cody-solutions-having-extremely-low-size
So it is indeed a sort of cheating? I wonder why it is allowed...
Mariano
on 17 Feb 2014
So do I. Wonder, I mean.
Camille Douay
on 7 Nov 2014
Thank you for the solution of the extremely low size solution
Dougal
on 6 Mar 2015
It's ironic. The size metric is meant to create most elegant solutions. At the same time it's more fun this way.
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1 Comment
Graig Ganitano
on 10 Aug 2013
Straight forward with a for loop. Could definitely be improved considering good code doesn't use loops.
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1 Comment
Shashikiran Rajashekar
on 7 Aug 2013
Checkout the built-in function "regexp"
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1 Comment
Hassan Javaid
on 23 Jul 2013
this code works but its score is 51 and thats not good.... so can anyone improve it i'll be grateful.
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1 Comment
Li Yjie
on 28 Mar 2015
are you ok?
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1 Comment
Bora Eryilmaz
on 20 Jun 2013
There can be no elements with <0 AND >10. The problem statement should say <0 OR >10.
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2 Comments
Sharan Girdhani
on 5 May 2013
I can't understand why is it coming out wrong?? o.O
Kirk
on 18 Dec 2013
You would need a loop going through each element of x to finish this... a very bad idea..
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1 Comment
Muhammad Imran
on 15 Jan 2013
hmmm
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2 Comments
Praveen Suvarna
on 21 Nov 2012
function y = cleanUp(x)
x=[5 17 -20 99 3.4 2 8 -6]
for i=1:8
if (x(i)<0||x(i)>10)
y(i)=NaN;
else
y(i)=x(i);
end
end
Can anybody tell what is wrong with this code so that it is not clearing test 2.
Aditya Suryavanshi
on 24 Dec 2012
Check this:Solution 181284.
x is input matrix which will vary rather being defined as in above program.
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1 Comment
Ricardo
on 17 Jul 2012
Ins't there an even easir way of doing this?
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2 Comments
Ahmad
on 16 Sep 2012
Brilliant
Anirudh Iyer
on 15 May 2013
impressive!
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1 Comment
Mark
on 1 Feb 2012
Does not work because of rounding error
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1 Comment
Vedad
on 21 Apr 2012
Inefficient code... My solution took 0.022746sec while this one took 0.255477. Although the size was 19...
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1 Comment
Sripathi Sriharsha
on 27 Jan 2012
It is working when I try!?
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